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Answer:
C₅H₈NO₄Na
Explanation:
Step 1: Given data
- Percentage by mass of Na in MSG: 13.6%
- Percentage by mass of C in MSG: 35.5%
- Percentage by mass of H in MSG: 4.8%
- Percentage by mass of N in MSG: 8.3%
- Percentage by mass of O in MSG: 37.8%
Step 2: Divide each percentage by the atomic mass of the element
Na: 13.6/22.99 = 0.592
C: 35.5/12.01 = 2.96
H: 4.8/1.01 = 4.75
N: 8.3/14.00 = 0.592
O: 37.8/16.00 = 2.36
Step 3: Divide all the number by the smallest one, i.e. 0.592
Na: 0.592/0.592 = 1
C: 2.96/0.592 = 5
H: 4.75/0.592 ≈ 8
N: 0.592/0.592 = 1
O: 2.36/0.592 ≈ 4
The empirical formula of MSG is C₅H₈NO₄Na.
Answer:
During World War II, rationing was implemented to control the equal distribution of items in short supply. Although the primary goal of rationing was equal distribution, a secondary goal was to free valuable factory resources for war production.
Explanation:
<u>Given:</u>
Dimensions of the room= 12 ft * 15 ft * 8.60 ft
<u>To determine:</u>
The amount of HCN that gives the lethal dose in the room with the given dimensions
<u>Explanation:</u>
As per the World Health Organization, the lethal dose of HCN is around 300 ppm
300 ppm = 300 mg of HCN/ kg of inhaled air
Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³
Now, 1 ft³ = 28316.8 cm³
Therefore, the calculated volume of air corresponds to:
1548 * 28316.8 = 4.383 * 10⁷ cm3
Density of air (at room temperature 25 C) = 0.00118 g/cm3
Thus mass of air corresponding to the calculated volume is
Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3
= 5.172*10⁴ g = 51.72 kg
Lethal amount of HCN corresponding to 51.72 kg of air would be.
= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg
Ans: Lethal dose of HCN = 15.5 g
Molar mass Na = 23 g/mol
23 g ------------- 6.02 x 10²³ atoms
4.56 x 10⁻² g ----- ? atoms
atoms = 4.56 x 10⁻² x ( 6.02 x 10²³ ) / 23
atoms = 2.74 x 10²² / 23
= 1.19 x 10²¹ atoms
hope this helps!