Mass of iron(III)oxide, Fe2O3 sample = 1.143*10^2 g
Molar mass of Fe2O3 = 159.69 g/mole
i.e. 1 mole of Fe2O3 weighs 159.69 g
Based on stoichiometry:
1 mole of Fe2O3 has 2 moles of Fe
Atomic mass of Fe = 55.85 g/mole
Therefore we can write:
159.69 g of Fe2O3 is composed of 2*55.85 g of Fe
Thus, amount of Fe present in 1.143*10^2 g sample of Fe2O3 is
= 1.143*10^2 * 2* 55.85/159.69
= 7.995*10^-1 g
Answer:
When electromagnetic radiations enter earth surface , it passes through several layers of our atmosphere in meantime some raditions get reflected back and some reaches to us .
Answer:
PbBr2 + 2HCl → 2HBr + PbCl2. Reaction Information. Lead(Ii) Bromide + Hydrogen Chloride = Hydrobromic Acid + Cotunnite. Reaction Type.
Explanation:
hope this helps
5.0=mo(1/2) ^ 5
5.0=mo (.031)
about 160/161.29
