Answer: 4.22 grams of solute is there in 278 ml of 0.038 M 
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
Now put all the given values in the formula of molality, we get

mass of
= 
Thus 4.22 grams of solute is there in 278 ml of 0.038 M 
Answer: 10.3 mol/l
Explanation: Molality = concentration c = n/V
Amount of substance n = m/M = 150 g / 58.44 g/mol =
2,5667 mol . c = 2.5667 mol / 0.25 l = 10.2669 mol/l
c =
In reaction 2 moles of SO2 reacts with 5 moles of C...
So for 0.5 mole of SO2 we should have the same ratio ...
C/SO2 = 5/2
Is that clear?
160gof CO2×1molof CO2\44g of CO2×1mole of C\1mol of CO2×12g of C\1mole of C=
43.63g of C