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omeli [17]
4 years ago
9

The mechanism for the reaction described by 2N2O5(g) ---> 4NO2(g) + O2(g) is suggested to be (1) N2O5(g) (k1)--->(K-1) NO2

(g) + NO3(g) (2) NO2(g) + NO3(g) --->(K2) NO2(g) + O2(g) + NO(g)
(3) NO(g) + N2O5(g) --->(K3) 3NO2(g) Assuming that [NO3] is governed by steady-state conditions, derive the rate law for the production of O2(g) and enter it in the space below.
Rate of reaction= ∆[O2]/∆t = ???
Chemistry
1 answer:
aliina [53]4 years ago
5 0
Go add me on Snapchat christian3cruz
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Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3
Goryan [66]

Answer:  4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Now put all the given values in the formula of molality, we get

0.038M=\frac{n}{0.278L}

n=0.0105mol  

mass of  Fe_2(SO_4)_3 = moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g

Thus 4.22 grams of solute is there in 278 ml of 0.038 M Fe_2(SO_4)_3

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3 years ago
Calculate the molarity of a 150 g NaCl in 250 ml solution.
Marizza181 [45]

Answer: 10.3 mol/l

Explanation: Molality = concentration c = n/V

Amount of substance n = m/M = 150 g / 58.44 g/mol  =

2,5667 mol . c = 2.5667 mol / 0.25 l = 10.2669 mol/l

c =

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How many moles of C are needed to react with 0.500 moles of SO2?
Natali5045456 [20]
In reaction 2 moles of SO2 reacts with 5 moles of C...

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C/SO2 = 5/2

Is that clear?
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