For Fraunhofer diffraction at a single slit would be represented by:
<span>a sinθ = mλ
</span><span>It should be noted that the angle needs be halved because we are only concerned with the angle between m=1 and m=0 and they gave you the angle between m=1 to the right of the center and m=1 on the left of the center. We calculate as follows:
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<span>a sin(45/2)=(1)(470)
a = 1228 nm
Hope this answers the question. Have a nice day.
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Its the first one: it supplies radiant energy
Krypton is the least metallic. Because it is a noble gas. The elements go from left to right in order of most to least metallic. Krypton is the farthest right out of all of the elements you listed.
Answer:
The required angular speed the neutron star is 10992.32 rad/s
Explanation:
Given the data in the question;
mass of the sun M = 1.99 × 10³⁰ kg
Mass of the neutron star
M = 2( M )
M = 2( 1.99 × 10³⁰ kg )
M = ( 3.98 × 10³⁰ kg )
Radius of neutron star R = 13.0 km = 13 × 10³ m
Now, let mass of a small object on the neutron star be m
angular speed be ω.
During rotational motion, the gravitational force on the object supplies the necessary centripetal force.
GmM = / R² = mRω²
ω² = GM = / R³
ω = √(GM = / R³)
we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²
we substitute
ω = √( ( 6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)
ω = √( 2.65466 × 10²⁰ / 2.197 × 10¹²
ω = √ 120831133.3636777
ω = 10992.32 rad/s
Therefore, The required angular speed the neutron star is 10992.32 rad/s
Answer:
Option A
Explanation:
The correct answer is Option A.
At room temperature, the resistance is equal to 100 ohms.
When the temperature is reduced to 77 K from room temperature, change in the resistance is very less.
The temperature coefficient of the resistivity of most of the metal is small for the metals which are approximately equal 0.01 /K.
hence, Change is only slightly.