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2 years ago

Kinetic energy increases as:

Physics

2 answers:

Akimi4 [234]2 years ago

5 0

C. Both mass and velocity increases

34kurt2 years ago

3 0

Kinetic energy formula is: 1/2 mv^2

M = mass

V = Velocity

So as kinetic energy increases, mass increases and velocity increases because mass and velocity are directly proportional to each other.

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How do you do this question?

umka2103 [35]

Explanation:

The moment of inertia of each disk is:

Idisk = 1/2 MR²

Using parallel axis theorem, the moment of inertia of each rod is:

Irod = 1/2 mr² + m (R − r)²

The total moment of inertia is:

I = 2Idisk + 5Irod

I = 2 (1/2 MR²) + 5 [1/2 mr² + m (R − r)²]

I = MR² + 5/2 mr² + 5m (R − r)²

Plugging in values:

I = (125 g) (5 cm)² + 5/2 (250 g) (1 cm)² + 5 (250 g) (5 cm − 1 cm)²

I = 23,750 g cm²

7 0

2 years ago

A 5 kg block is pushed across a table by a horizontal force of 40 N with an acceleration of 5 m/s^2. What is the frictional forc

julsineya [31]

Answer:

Explanation:

mass, M = 5Kg

horizontal force, F_h = 40N

acceleration, a =5 m/s^2

frictional force, F_f =?

net force = ma

net force = F_h - F_f = 40N - F_f

40 - F_f = 5 x 5

- F_f = 25 - 40

multiply both side by -1

F_f = 40 - 25 = 15

the frictional force is 15N

4 0

2 years ago

The fast French train known as the TGV (Train à Grande Vitesse) has a scheduled average speed of 216 km/h. (a) If the train goes

faust18 [17]

Answer:

a) r = 6122 m and b) v = 32.5 m / s

Explanation:

a) The train in the curve is subject to centripetal acceleration

a = v2 / r

Where v is The speed and r the radius of the curve

They indicate that the maximum acceleration of the person is 0.060g,

a = 0.060 g

a = 0.060 9.8

a = 0.588 m /s²

Let's calculate the radius

v = 216 km / h (1000m / 1km) (1 h / 3600 s =

v = 60 m / s

r = v² / a

r = 60² /0.588

r = 6122 m

b) Let's calculate the speed, for a radius curve 1.80 km = 1800 m

v = √a r

v = √( 0.588 1800)

v = 32.5 m / s

6 0

3 years ago

A student has a weight of 655 N. While riding a roller coaster they seem to weigh 1.96x 103 N at the bottom of a dip that has a

Nadya [2.5K]

Answer:

The speed of the roller coaster at this point is 18.74 m/s.

Explanation:

Given that,

Weight of the student, W = 655 kg

Weight of the roller coaster, $F=1.96\times 10^3\ N$

Radius of the roller coaster, r = 18 m

At the bottom of the loop, the weight of the roller coaster us given by :

$F=W+\dfrac{mv^2}{r}$

If m is the mass of the roller coaster,

$W=mg$

$m=\dfrac{W}{g}$

$m=\dfrac{655}{9.8}$

m = 66.83 kg

So,

$F=W+\dfrac{mv^2}{r}$

$v=\sqrt{\dfrac{(F-W)r}{m}}$

$v=\sqrt{\dfrac{(1.96\times 10^3-655)\times 18}{66.83}}$

v = 18.74 m/s

So, the speed of the roller coaster at this point is 18.74 m/s. Hence, this is the required solution.

4 0

3 years ago

Read 2 more answers

What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a w

Delvig [45]

(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by
$f_1 = \frac{1}{2L} \sqrt{ \frac{T}{m/L} }$
where
L is the wire length
T is the tension
m is the wire mass

In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is
$T= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }= \frac{1}{2 \cdot 10.9 m} \sqrt{ \frac{253 N}{0.0558 kg/10.9 m} }= 10.2 Hz$

b) The frequency of the nth-harmonic for a standing wave in a wire is given by
$f_n = n f_1$
where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:
$f_2 = 2 f_1 = 2 \cdot 10.2 Hz=20.4 Hz$

c) Similarly, the third lowest frequency (third harmonic) is given by
$f_3 = 3 f_1 = 3 \cdot 10.2 Hz = 30.6 Hz$

8 0

2 years ago

Kinetic energy increases as:￼

Kinetic energy increases as: