1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dimas [21]
3 years ago
10

Why is silver metal precious but not as precious as gold

Chemistry
2 answers:
Soloha48 [4]3 years ago
4 0

Explanation:

Because the greater the scarcity, the higher its price ... That is, silver is more present than gold

marissa [1.9K]3 years ago
4 0
Silver Is Easier To Find Which Makes Silver Cheaper Than Gold.
You might be interested in
A chemist prepares a solution of sodium chloride(NaCl) by measuring out 25.4g of sodium chloride into a 100ml volumetric flask a
labwork [276]

Answer: 4 molL-1

Explanation:

Detailed solution is shown in the image attached. The number of moles of NaCl is first obtained. Since the molarity must be in units of molL-1, the volume is divided by 1000 and the formula stated in the solution is applied and the answer is given to one significant figure.

5 0
3 years ago
Read 2 more answers
Purification of nickel can be achieved by electrorefining nickel from an impure nickel anode onto a pure nickel cathode in an el
Alexxandr [17]

Answer: 530 hours

Explanation:

The reduction of Nickel ions to nickel is shown as:

Ni^{2+}+2e^-\rightarrow Ni

96500\times 2=193000Coloumb of electricity deposits 1 mole of Nickel

1 mole of Nickel weighs = 58.7 g

Given quantity = 18.0 kg = 18000 g  (1kg=1000g)

58.7 g of Nickel is deposited by 193000 C of electricity

18000 g of Nickel is deposited by = \frac{193000}{58.7}\times 18000=59182282.8C of electricity

Q=I\times t

where Q= quantity of electricity in coloumbs  = 59182282.8C

I = current in amperes = 31.0 A

t= time in seconds = ?

59182282.8C=31.0A\times t

t=1909105.9sec

(1h=3600 sec)

t=530hours

Thus 530 hours are required to plate 18.0 kg of nickel onto the cathode if the current passed through the cell is held constant at 31.0 A

3 0
3 years ago
Quick question: Are water molecules attracted to each other because of the polar nature of water?
Colt1911 [192]

Answer:

Because the opposite charge between them

Explanation:

4 0
3 years ago
Which of the following is TRUE? A) The equivalence point is where the amount of acid equals the amount of base during any acid-b
liberstina [14]

Answer:

the correct option is B

Explanation:

The correct option is b, since if we reach pH 7, it means that the acid-base reaction is neutralized, therefore the base has been neutralized by an acid or vice versa, without taking into account the proteins or the amounts of both components .

5 0
3 years ago
Read 2 more answers
To help relieve heartburn, a person should take medicine that is
Sav [38]

Prescribed to you by your doctor.

I would use an over the counter antacids for occasional heart burn. If there are symptoms of acid reflux I would suggest a histamine blocker, or H2-Blockers, such as Ranitidine (Zantac) and Famotidine (Pepcid)

3 0
3 years ago
Read 2 more answers
Other questions:
  • What is the total amount of heat required to completely melt 347 grams of ice at t's melting point
    15·2 answers
  • The chart indicates the time, speed, and velocity of five runners.
    6·1 answer
  • What do you think the volume of a perscription bottle would be?<br> plz help me
    11·1 answer
  • What causes a disturbance that results in a wave
    10·2 answers
  • How are plastic containers and paper containers the same
    12·1 answer
  • What is arcade in south Center
    5·1 answer
  • In a few words, what would you expect the weather to be like in El Paso, Texas?
    12·1 answer
  • What is the pH of a solution with a 3.2 x 10−6 M hydronium ion concentration?
    9·1 answer
  • Select the correct answer.
    11·1 answer
  • Express each of the following numbers in exponential notation:SHOW YOUR WORK
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!