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garik1379 [7]
2 years ago
8

What is the molarity of a HCl solution that

Chemistry
2 answers:
ipn [44]2 years ago
5 0

Answer:

M = 1.04 M

Explanation:

Given data:

Molarity of solution = ?

Mass of HCl = 6.27 g

Volume of solution = 163 mL (163 mL× 1L /1000 mL = 0.163 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 6.27 g / 36.5 g/mol

Number of moles = 0.17 mol

Molarity:

M = 0.17 mol/ 0.163 L

M = 1.04 M

sergejj [24]2 years ago
3 0

Answer:

4.6 M HCI

Explanation:

on edge

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When the following equation is balanced, what is the coefficient for NaNO3?
notka56 [123]

The coefficient for NaNO₃ = 6

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

AI(NO₃)₃ +Na₂SO₄ → Al₂(SO₄) + NaNO₃

give coefficient

aAI(NO₃)₃ +bNa₂SO₄ → Al₂(SO₄)₃ +c NaNO₃

Al, left=a, right=2⇒a=2

N, left=3a, right=c⇒3a=c⇒3.2=c⇒c=6

Na, left=2b, right=c⇒2b=c⇒2b=6⇒b=3

The equation becomes :

2AI(NO₃)₃ +3Na₂SO₄ → Al₂(SO₄)₃ +6NaNO₃

6 0
3 years ago
A sample of gas occupies 1.2 L at 12.0oC. Assuming pressure remains the same, what would be the volume (in L) of this gas at 67o
Levart [38]

Answer:

e.

6.7

hope it help

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4 0
3 years ago
Where are metals, nonmetals, metalloids, and the noble gases located on the periodic table?
Fofino [41]
Metals are on the left side of the table and nonmetals are on the left with metalloids between them. And the noble gases are all in group 18 of the periodic table.
6 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
What is the number placed in front of a compound to balance a chemical reaction?
stiks02 [169]

coefficient: they balance the chemical equation you have to make sure the number is as small as it can. It is also used to convert different compounds to compounds or quantities to quantities.

5 0
3 years ago
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