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Tanzania [10]
3 years ago
12

What is the efficiency of a car's engine when heat input is 400,000 joules and

Physics
2 answers:
Aleksandr-060686 [28]3 years ago
5 0
Either 25% or 75%. does it to how much is wasted or the difference in the input and waste?
otez555 [7]3 years ago
3 0

Answer: A. 25%

Explanation: Ap3x

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If gravity on the earth increased, what affect would it have on the moon
Rufina [12.5K]

Answer:

If gravity on Earth is increased, this gravitational tugging would have influenced the moon's rotation rate. If it was spinning more than once per orbit, Earth would pull at a slight angle against the moon's direction of rotation, slowing its spin. If the moon was spinning less than once per orbit, Earth would have pulled the other way, speeding its rotation.

6 0
3 years ago
What two quantities must stay the same in order for an object to have a constant velocity? A) The speed and kinetic energy must
GarryVolchara [31]

the answer is c) the speed and direction of travel must be constant


7 0
4 years ago
“Anchor” points on a temperature scale are known as fiducial points.<br><br> a)True<br> b)False
Svetlanka [38]
Yes. It r<span>efers to any of the temperatures assigned to a number of reproducible equilibrium states on the International Practical Temperature Scale</span><span>

In short, Your Answer would be "True"

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8 0
3 years ago
Read 2 more answers
The sound intensity at a distance of 16 m from a noisy generator is measured to be 0.25 W/m2. What is the sound intensity at a d
Margarita [4]

Answer:

0.1111 W/m²

Explanation:

If all other parameters are constant, sound intensity is inversely proportional to the square of the distance of the sound. That is,

I ∝ (1/r²)

I = k/r²

Since k can be the constant of proportionality. k = Ir²

We can write this relation as

I₁ × r₁² = I₂ × r₂²

I₁ = 0.25 W/m²

r₁ = 16 m

I₂ = ?

r₂ = 24 m

0.25 × 16² = I₂ × 24²

I₂ = (0.25 × 16²)/24²

I₂ = 0.1111 W/m²

4 0
3 years ago
To practice problem-solving strategy 9.1 a strategy for conservation of momentum problems. an 80-kg quarterback jumps straight u
kherson [118]
Refer to the diagram shown below.

By definition momentum =  mass *  velocity.

Before throwing the ball:
The initial momentum is
P₁ = 0.

After throwing the ball:
Let u = the backward velocity of the quarterback.
The momentum is 
P₂ = (0.43 kg)*(15 m/s) + (80 kg)*(- u m/s)

Conservation of momentum requires that
P₂ = P₁
6.45 - 80u = 0
u = 6.45/80 = 0.0806 m/s

Answer: 0.08 m/s backward

6 0
3 years ago
Read 2 more answers
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