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castortr0y [4]
3 years ago
14

A 120.0 kg crate is placed on a 15.00°

Physics
1 answer:
Citrus2011 [14]3 years ago
7 0

F = 2820.1 N

Explanation:

Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as

Fnet = ma = 0 (a = 0 no sliding)

= F - mgsin15°

= 0

or

F = mgsin15°

= (120 kg)(9.8 m/s^2)sin15°

= 2820.1 N

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How can you use the movement of molecules to determine when a phase change has occurred?
baherus [9]

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A train whistle has a sound intensity level of 70. dB, and a library has a sound intensity level of about 40. dB. How many times
kodGreya [7K]

Answer:

The sound intensity of train is 1000 times greater than that of the library.

Explanation:

We have expression for sound intensity level,

            L=10log_{10}\left ( \frac{I}{I_0}\right )

A train whistle has a sound intensity level of 70 dB

We have

           70=10log_{10}\left ( \frac{I_1}{I_0}\right )

A library has a sound intensity level of about 40 dB

We also have

           40=10log_{10}\left ( \frac{I_2}{I_0}\right )

Dividing both equations

           \frac{70}{40}=\frac{10log_{10}\left ( \frac{I_1}{I_0}\right )}{10log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\\frac{7}{4}=\frac{log_{10}\left ( \frac{I_1}{I_0}\right )}{log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\10^7\frac{I_2}{I_0}=10^4\frac{I_1}{I_0}\\\\\frac{I_1}{I_2}=10^3=1000

The sound intensity of train is 1000 times greater than that of the library.

3 0
2 years ago
Two electric motors drive two elevators of equal mass in a three-story building 10 meters tall. Each elevator has a mass of 1,00
algol [13]

Answer:

The power output of the first motor is,  P = 2.0 x 10⁴ watts

Explanation:

Given data,

The height of the building, h = 10 m

The mass of the elevator, m = 1000 kg

The time duration of the motor to do this work, t = 5.0 s

The force acting on the elevator,

                                  F = m x g

                                    = 1000 x 9.8

                                     = 9800 N

The work done by the elevator,

                                W = F  x h

                                     = 9800 x 10

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The power output of the first motor,

                                P = W / t

                                   = 98000 / 5

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Hence, the power output of the first motor is, P = 2.0 x 10⁴ watts

3 0
3 years ago
What is the momentum of a vehicle that has a mass of 800 kg and is moving at a velocity of 5 m/s
yarga [219]

Answer:

4000 kg.m/s

Explanation:

p=mv

m=800 kg

v=5 m/s

p=(800)(5)= 4000 kg.m/s

3 0
3 years ago
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