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3 years ago

Which is NOT a property of metals? Group of answer choices luster brittleness conductivity ductility

2 answers:

6 0

As you probably already know, ductility is the ability of a metal to receive permanent deformation without fracturing. Metals that can be formed or pressed into another shape without fracturing are ductile. In general, all metals are ductile at elevated temperatures.

Since metals bend by creating and moving dislocations, the near absence of dislocation motion causes brittleness. On the positive side, the difficulty of moving dislocations makes quasicrystals extremely hard. They strongly resist deformation.

Conductivity in metal is a measure of a material's ability to transmit heat, or electricity (or sound). The reciprocal of conductivity is resistance, or the ability to reduce the flow of those.

Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other properties include: ... Luster: Metals have the quality of reflecting light from its surface and can be polished e.g., gold, silver and copper.

Chose which one you thing it is.

ki77a [65]3 years ago

5 0

Answer:

wait i am kinda counfuesd

Explanation:

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4 years ago

Which change in the sun’s gravity would occur if the sun’s mass were reduced by one-half?(1 point)

Kisachek [45]

Answer:

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Explanation:

The gravity of an object can be determined using the formula:

$\text{g}&=\frac{\text{GM}}{\text{R}^{2} }}$

Now, according to the question, the mass of the sun is halved, which will be written as:

$\text{g}&=\frac{\text{G}\frac{\text{M}}{2}}{\text{R}^{2} }}$

Thus, according to the equation, the mass of an object is directly proportional to the gravitational field. since, the mass of the Sun is reduced to half, the gravity of the Sun will be halved.

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3 years ago

Read 2 more answers

How much heat energy would be released if 78.1 g of water at 0.00 °c were converted to ice at −57.1 °c. give your answer as a po

kolezko [41]

To convert 78.1 g of water at 0° C to Ice at -57.1°C; we can do it in steps;
1. Water at 0°C to ice at 0°C
The heat of fusion of ice is 334 J/g;
Heat = 78.1 × 334 = 26085.4 Joules
2. Ice at 0°C to -57.1°C
Specific heat of ice is 2.108 J/g
Heat = 78.1 × 2.108 J/g = 164.6348 Joules
Thus the total heat energy released will be; 26085.4 + 164.6348
= 26250.0348 J or 26.250 kJ

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3 years ago