Answer:
s = 589.3 m
Explanation:
Let the truck and car meet at a distance = s m
The truck is moving at constant velocity = v
so s= v * t ---------- (1)
car:
Vi = 0 m/s
a = 3.9 m/s²
s = Vi* t + 1/2 a t²
s= 0 * t + 1/2 a t²
s = 1/2 a t² ----------- (2)
compare equation (1) and equation (2)
s= v * t = 1/2 a t²
⇒ v * t = 1/2 a t²
⇒ t = 2 * v/ a
⇒ t = (2 * 33.9 )/ 3.9
⇒ t = 17. 38 s
Now
from equation (1)
s= v * t
s= 33.9 * 17.38
⇒ s = 589.3 m
Answer:
2.61 atm
Ley de Boyle
Explanation:
= Presión inicial = 0.96 atm
= Presión final
= Volumen inicial = 95 mL
= Volumen final = 35 mL
En este problema usaremos la ley de Boyle.

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.
3 protons should be your answer
It is 29 and a half days long
Answer:
They will meet at a distance of 7.57 m
Given:
Initial velocity of policeman in the x- direction, 
The distance between the buildings, 
The building is lower by a height, h = 2.5 m
Solution:
Now,
When the policeman jumps from a height of 2.5 m, then his initial velocity, u was 0.
Thus
From the second eqn of motion, we can write:


t = 0.707 s
Now,
When the policeman was chasing across:


The distance they will meet at:
9.57 - 2.0 = 7.57 m