Answer:
The electron domain and molecular geometry of NF₃ are option b
Explanation:
First of all, think the total valence electrons of each element.
N : 5
F: 7, but we have 3, so 7.3 = 21
Total: 26 e⁻
Now let's draw a scheme
F ---- N ---- F
|
F
We have to put 26 e⁻ around the elements, so 6 e⁻ are been used for the bonds N-F, so now, there are 20 e⁻ to add. As the F, have used 1 e⁻ to form the bond, there are 6 more, around. Each fluorine which has 7 e⁻, shares 1e⁻ with the N, to complete the octet rule.
So, there are still 2e⁻ to add. They will be above the N and they are free. That's why the molecular geometric is trigonal, and the electronic geeometry is tetrahedral because the non-binding electron pair of N
4Li + O₂ ⇒ 2Li₂O
Li₂O = 2/4 x 3.33 = 1.665
Answer:
1.2044 x 10^24 particles
Explanation:
Assuming this is<u> STP</u>....then this is 2 moles ( each mole = 22.4 L/mole)
2 moles = 2 * 6.022 x 10^23 = 1.2044 x 10^24
5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
We have 231 g of gold at 18 °C and supply it with heat to increase its temperature to 195 °C. We can calculate the amount of heat required using the following expression.
where,
- <em>c: specific heat capacity of gold</em> (0.129 J/g.°C)
- ΔT: change in the temperature
5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.
You can learn more about heating here: brainly.com/question/1105305
