Use the density to convert volume into mass.
since the density is in g/ml and the volume was given in Liters, we need to first convert the Liters into mililiters. just multiply by 1000 or move the decimal three times.
0.1200 Liters= 120.0 mL
120.0 mL (0.8787 grams/ 1 mL)= 105 grams
1 mole = 6.022×10^23 atoms. 1 water molecule = 2 Hydrogen atoms + 1 oxygen atom. So, 1 mole H2O = 1.2044×10^24 hydrogen atoms. Therefore 2 mole H2O will have 2.4088×10^24 hydrogen atoms.
If this is just a general question it seems to vary from about 4.5g to 5g. Is there more data to the question?
The characteristics of wave are amplitude, speed , frequency and wavelength.
<u>Explanation:</u>
Amplitude is defined as the distance covered by the particles or molecules moving in a wave nature. So the maximum positive and negative peak position is termed as amplitude of the wave.
Every wave forms a series of crests and trough regions. The crest region is the positive amplitude while the trough region is the negative amplitude. The distance between two successive crests and troughs are termed as wavelength.
A single crest and trough forms a complete cycle. So the number of times a cycle is repeated for a given time is known as frequency. Speed is defined as the product of frequency and wavelength of the wave. In other words, speed of a wave is the rate at which the particles are moving a given area per unit time.
Answer:
NO would form 65.7 g.
H₂O would form 59.13 g.
Explanation:
Given data:
Moles of NH₃ = 2.19
Moles of O₂ = 4.93
Mass of NO produced = ?
Mass of produced H₂O = ?
Solution:
First of all we will write the balance chemical equation,
4NH₃ + 5O₂ → 4NO + 6H₂O
Now we will compare the moles of NO and H₂O with ammonia from balanced chemical equation:
NH₃ : NO NH₃ : H₂O
4 : 4 4 : 6
2.19 : 2.19 2.19 : 6/4 × 2.19 = 3.285 mol
Now we will compare the moles of NO and H₂O with oxygen from balanced chemical equation:
O₂ : NO O₂ : H₂O
5 : 4 5 : 6
4.93 : 4/5×4.93 = 3.944 mol 4.93 : 6/5 × 4.93 = 5.916 mol
we can see that moles of water and nitrogen monoxide produced from the ammonia are less, so ammonia will be limiting reactant and will limit the product yield.
Mass of water = number of moles × molar mass
Mass of water = 3.285 mol × 18 g/mol
Mass of water = 59.13 g
Mass of nitrogen monoxide = number of moles × molar mass
Mass of nitrogen monoxide = 2.19 mol × 30 g/mol
Mass of nitrogen monoxide = 65.7 g
