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3 years ago

Using your own words, how would you explain how orbits work?

2 answers:

7 0

<h2>Answer:</h2><h2>It's a repeating part that one object in space takes around one another.</h2>

LuckyWell [14K]3 years ago

7 0

An orbit is the gravitationally curved trajectory of an object, or in other words, why and how our planets make their way around the sun, which also causes the seasons to “change,” why we have colder weather, warmer weather, and why we have night and day.

I hope this helps!

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A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat

Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

$s=ut-\dfrac{1}{2}at^2$

Put the value into the formula

$1200=92t+\dfrac{1}{2}\times4t^2$

$2t^2+92-1200=0$

$t=10\ sec$

We need to calculate the velocity

Using equation of motion

$v=u+at$

Put the value into the formula

$v=92+4\times10$

$v=132\ m/s$

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

$h'=h+ut-\dfrac{1}{2}at^2$

Put the value into the formula

$0=1200+132t-\dfrac{1}{2}\times9.8t^2$

$4.9t^2-132t-1200=0$

$t=34\ sec$

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

$t'=34+10$

$t'=44\ sec$

Hence, The rocket above the ground is in 44 sec.

7 0

4 years ago

A force of 6.0 Newton’s gives a 2.0kg block an acceleration of 3.0m/s to the right. The force of friction acting on the block is

DochEvi [55]

The force of friction is zero.
Using F = m a = the force needed is 6 N which means no friction can be acting.

3 0

4 years ago

A 1 kg ball moving horizontally to the right at 3 m/s strikes a wall and rebound, moving horizontally to the left at the same ve

Airida [17]

Answer:

The magnitude of the change in linear momentum of the ball is 6 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 1 kg

Initial sped of the ball, u = 3 m/s

It strikes a wall and rebound, moving horizontally to the left at the same velocity of 3 m/s, v = -3 m/s

The magnitude of the change in linear momentum of the ball is given by :

$p=m(v-u)\\\\p=1\ kg\times (-3-3)\\\\p=-6\ kg-m/s$

So, the magnitude of the change in linear momentum of the ball is 6 kg-m/s.

3 0

4 years ago

When vibrational motion in an object increases, which is a true statement?

Step2247 [10]

When vibrational motion in an object increases, the statement that is true is that the kinetic energy temperature and thermal energy increases. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer comes to your help.

6 0

3 years ago

Describe the difference between nuclear energy and light energy

mr Goodwill [35]

Light energy is more controlled than nuclear

6 0

4 years ago