Use the formula:
E = (1/2) * m * v ^2
For unit consistency, make sure that:
E energy is in joules (J)
m mass is in kilograms (kg)
v velocity is in meters per second (m/s)
So, substituting to the equation:
14= (1/2) * (17) * v^2
By algebraic manipulation, we derive:
v = (2*14/17)^0.5
v = 1.2834 m/s
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Related Questions (More Answers Below)
The distance traveled by the egg after 2 seconds is 19.6 m.
The given parameters:
- <em>Height of the window, h = 40 m</em>
The distance traveled by the egg after 2 seconds is calculated as follows;

where;
- <em />
<em> is the initial vertical velocity of the egg = 0</em> - <em>g </em><em>is acceleration due to gravity = 9.8 m/s²</em>
- <em>t </em><em>is the time of motion, = 2 s</em>

Thus, the distance traveled by the egg after 2 seconds is 19.6 m.
Learn more about second equation of motion here: brainly.com/question/7977693
Kinetic energy formula: Ek = m · v² / 2
We have: m= 3 kg, v= ?
h= g·t²/2 , t²= 2h/g = 2 m / 9.81 m/s² = 0.2 s² , t=√0.2(sqrt)= 0.45 s
v= g· t = 9.81 m/s² · 0.45 s = 4.43 m/s
Finally: Ek=

=
29.43 J