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3 years ago

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A 123-turn circular coil of radius 2.41 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coi

l. During 0.151 s the magnetic field strength increases from 50.9 mT to 96.3 mT. Find the magnitude of the average EMF, in millivolts, that is induced in the coil during this time interval.

1 answer:

klasskru [66]3 years ago

8 0

Answer:

67.44 V

Explanation:

Number of turns N =123

Radius = 2.41 cm =0.0241 m

The magnetic field strength increases from 50.9 T to 96.3 T so change in magnetic field dB = 96.3-50.9=45.4 T

Time interval dt = 0.151 sec

We know that the induced emf $e=-NA\frac{dB}{dt}$

Area $A=\pi r^2=3.14\times 0.0241^2=1.8237\times 10^{-3}m^2$

Putting all these values in emf equation $e=-123\times 1.8237\times 10^{-3}\times \frac{45.4}{0.151}=-67.44\ V$ here negative sign indicates that it opposes the cause due to which it is produced

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<u>Accelerated Motion </u>

When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

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$\displaystyle \boxed{X_T=66.6\ km}$

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