A skier is traveling at a speed of 34.7 m/s when she reaches the base of a frictionless ski hill. This hill makes an angle of 10
^o with the horizontal. She then coasts up the hill as far as possible. What height (measured vertically above the base of the hill) does she reach?
1 answer:
Answer:
h = 61.5m
Explanation:
Initial speed = 34.7m/s
Net force =
F= -mg Sin 10
We are finding distance moved by this skier upon the hill.
ma = - mgSin10
a = -gSin10
g = 9.8
Sin 10 = 0.1564
a = -9.8(0.1564)
a = -1.53
This is the acceleration
(-34.7)² = 2as
= -34.7² = (-2x1.53)s
-1204.09 = -3.06s
We find the value of s
S = -1204.09/-3.06
S = 393.5m
Sin10 = h/393.5m
0.1564 = h/393.5m
h = 0.1564x393.5m
h = 61.5
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