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alexgriva [62]
2 years ago
10

The pyruvic acid from glycolysis can be converted to acetic acid, which can enter the citric acid cycle. Because this process is

a cycle, the atoms entering the cycle must balance the atoms that leave. Consider carbon balance in the citric acid cycle. How many CO2 molecules leave the cycle for each acetic acid molecule that enters? For this question, assume that carbon only enters as acetic acid and exits as CO2 . Note that acetic acid has two carbon atoms. You can determine the number of carbon atoms in carbon dioxide from its formula, CO2 .
Chemistry
1 answer:
galina1969 [7]2 years ago
4 0

Answer:

The correct answer is - 2CO2 or two molecules of carbon dioxide.

Explanation:

The TCA cycle or citric acid cycle is a central pathway of cellular respiration that helps in unifying several metabolites and generates energy for cellular functions. It takes place over eight different steps:

Step 1:  Acetyl CoA enters the citric acid cycle that is a 2-carbon compound and attaches with 4-carbon compound oxaloacetate to form citrate a 6 carbon compound

Step 2: This 6-carbon compound isocitrate

Step 3: 5 carbon compound alpha-ketoglutarate is produced by oxidizing the isocitrate and release the release of carbon dioxide. One NADH molecule is formed.

Step 4: This 5 carbon molecule is oxidized again to form a four-carbon compound that binds with CoA to make forming succinyl CoA. A second molecule of NADH is produced, alongside a second molecule of carbon dioxide.

Step 5: Succinyl CoA is then converted to succinate with GTP formation

Step 6: Succinate is converted into fumarate with the generation of FADH₂ molecule.

Step 7: Fumarate is converted to malate

Step 8: oxaloacetate is formed with the NADH molecule.

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Calculate the molality of each of the following solutions: (a) 36.2 g of sucrose (C12H22O11) in 323 g of water, m (b) 8.63 moles
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Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by firstly considering the fact that the molality is computed by dividing the moles of solute by the kilograms of solvent, in this case water; in such a way, we proceed as follows:

(a) We firstly calculate the moles of 36.2 grams of sucrose as its molar mass is 342.3 g/mol:

\frac{36.2g}{342.3g/mol} =0.106mol

Next, the kilograms of water in this case are 0.323 kg so that the molality will be:

m=\frac{0.106mol}{0.323kg}\\\\m=0.327m

(b) In this case, we directly realize that the kilograms of water are now 1.889 kg so that the molality will be:

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