Answer:
32.4%
Explanation:
Given parameters:
Mass of hydrated sample = 25g
Mass of anhydrous salt = 16.9g
Unknown:
Percentage of water in the hydrate = ?
Solution:
Obviously, there is a mass difference between the original hydrated sample and anhydrous salt which should indicate clearly that the mass loss is due to the evaporated water from the salt.
Mass of salt of water = mass of hydrated salt - mass of anhydrous salt
= 25g - 16.9g
= 8.1g
Percentage of water =
=
= 32.4%
20 B203(s) + 12180 HF(l) = 4060 BF3(g) + 609 H20(l)
Answer:
A symbolic way to show a chemical reaction is a chemical equation.
X * 0.10 mg/mL = 0.50 mg
x = 0.50 mg / 0.10
x = 5.0 mL
hope this helps!
Answer:
0.4675 atm, 355.3 mmHg
Explanation:
Given:
Pressure = 355.3 torr
The conversion of P(torr) to P(atm) is shown below:
So,
Pressure = 355.3 / 760 atm = 0.4675 atm
The conversion of P(torr) to P(mmHg) is shown below:
So,
Pressure = 355.3 mmHg