The chemical reaction between the reactants:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Explanation:
We have the following chemical reaction:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Complete ionic equation:
3 Ag⁺ (aq) + 3 NO₃⁻ (aq) + Fe³⁺ (aq) + 3 Cl⁻ (aq) → 3 AgCl (s) + Fe³⁺ (aq) + 3 NO₃⁻ (aq)
We remove the spectator ions and we get the net ionic equation:
Ag⁺ (aq) + Cl⁻ (aq) → AgCl (s)
where:
(aq) - aqueous
(s) - solid
Learn more about:
net ionic equation
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A good example of equilibrium would be the mixing of oil and water in a closed container.
<h3>What is chemical equilibrium?</h3>
Chemical equilibrium is a condition in which the concentrations of components of a chemical reaction remain unchanged and have no tendency to change.
Of all the options, the only one where the concentrations of the component reactants cannot change is a mixture containing oil and water in a closed container.
Oil and water are immiscible and thus, their concentrations remain constant.
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Answer:
(a) See below
(b) 103.935 °F; 102.235 °F
Explanation:
The equation relating the temperature to time is

1. Calculate the thermometer readings after 0.5 min and 1 min
(a) After 0.5 min

(b) After 1 min

2. Calculate the thermometer reading after 2.0 min
T₀ =106.321 °F
ΔT = 100 - 106.321 °F = -6.321 °F
t = t - 1, because the cooling starts 1 min late

3. Plot the temperature readings as a function of time.
The graphs are shown below.
The freezing point depression is calculated through the equation,
ΔT = (kf) x m
where ΔT is the difference in temperature, kf is the freezing point depression constant (1.86°C/m), and m is the molality. Substituting the known values,
5.88 = (1.86)(m)
m is equal to 3.16m
Recall that molality is calculated through the equation,
molality = number of mols / kg of solvent
number of mols = (3.16)(1.25) = 3.95 moles
Then, we multiply the calculated amount in moles with the molar mass of ethylene glycol and the answer would be 244.9 g.
Answer:
131 atm
Explanation:
To find the new pressure, you need to use Boyle's Law:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new pressure (P₂) by plugging the given values into equation and simplifying.
P₁ = 3.88 atm P₂ = ? atm
V₁ = 7.74 L V₂ = 0.23 L
P₁V₁ = P₂V₂ <----- Boyle's Law
(3.88 atm)(7.74 L) = P₂(0.23 L) <----- Insert values
30.0312 = P₂(0.23 L) <----- Simplify left side
131 = P₂ <----- Divide both sides by 0.23