The modern periodic table can be divided into ____________and _______________

The pH of a solution prepared by mixing 40.00 mL of 0.10 M NH3 with 50.00 mL of 0.10 M NH4Cl and 30mL of 0.05 M H2SO4 is 5.17. A

liq [111]

Answer:

Following are the answer to this question:

Explanation:

The value of pH solution is =5.17 So, the p^{OH}:

$p^{OH}$ =14-56.17

=8.823

The volume of the $NH_{3}$ = 40.00 ml

convert into the liter= 0.040L

The value of the concentrated $NH_{3}$ =0.10 M

The volume of the $NH_{4}Cl$ = 50.00 ml

convert into the liter= 0.050L

The value of concentrated $NH_{4}Cl$ = 0.10 M

The volume of the $H_{2}So_{4}$ = 30 ml

convert into the liter= 0.030L

The value of concentrated $H_2So_4$ =0.05 M

Calculating total volume=(0.40+0.050+0.030)

=0.120 L

calculating the new concentrated value of $NH_3$ = $\frac{0.10\times 0.040}{0.120}= 0.33 \ M$

calculating the new concentrated value of $NH_4Cl$ = $\frac{0.050\times 0.10}{0.120}= 0.04166 \ M$ calculating the new concentrated value of $H_2So_4= \frac{0.030\times 0.05}{0.120}= 0.0125 \ M$ when 1 mol $H_2So_4$ produced 2 mols $H^{+}$ so, 0.0125 in $H_2So_4$ produced:

$=4 \times (2 \times 0.0125) \ mol H^{+}\\\\= 0.025 mol H^{+}$

create the ICE table:

$NH_3 \ \ \ \ \ \ \ \ + H^{+} \ \ \ \ \ \ \longrightarrow NH_4^{+}$

I (m) 0.033(m) 0.025 0.04166

C -0.025 -0.025 + 0.025

E 8.3\times 10^{-3} 0 0.0667

now calculating pH:

when ph= 8.83:

$P^{H}= p^{kb}|+ \log\frac{[NH_4^{+}]}{[NH_3]}\\\\8.83=p^{kb}+\log\frac{0.0667}{8.3 \times 10^{-3}}\\\\p^{kb}=8.83-0.9069\\\\ \ \ \ =7.7231 \\\\\ The P^{kb} \ for \ NH_3 \ is =7.7231\\\\\ The P^{kb} \ for N^{+}H_4=14-7.7231\\\\\ \ \ \ \ \ =6.2769$

5 0

3 years ago

if you are told to get 100 mL of stock solution to use to prepare smaller size sample for an experiment, which piece of glasswar

fgiga [73]

Answer:

A beaker

Step-by-step explanation:

Specifically, I would use a 250 mL graduated beaker.

A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.

You don't need precisely 100 mL solution.

If the beaker is graduated, you can easily measure 100 mL of the stock solution.

Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).

6 0

3 years ago

What is the Mechanical advantage of a machine that only changes the direction of the force?

Sloan [31]

Answer: 1

Explanation:

The number of times a machine increases a force exerted on it The input force will be the same as the output force.

6 0

3 years ago

The dark areas on the map show the distribution of coral reefs around the world. What explanation best

arsen [322]

Answer:

I think is D not sure

Explanation:

8 0

2 years ago

What is the molecular formula of the following compound: NH_CI, molar mass = 51.5 g/mol?

Helen [10]

Answer:

Explanation:

Explanation:

As you know, the empirical formula tells you what the smallest whole number ratio that exists between the atoms that make up a compound is.

In your case, you know that the empirical formula is

NH Cl

2

, which means that the regardles of how many atoms of each element you get in the actual compound, the ratio that exists between them will always be

1:2:1.

What you actually need to determine is how many empirical formulas are needed to get to the molecular formula.

Notice that the problem provides you with the molar mass of the compound. This means that you can use the molar mass of the empirical formula to determine exactly how many atoms you need to form the compound's molecule.

molar mass empirical formula×n=molar mass compound

To get the molar mass of the empirical formula, use the molar masses of its constituent atoms

14.0067 g/mol+2×1.00794 g/mol+35.453 g/mol=51.48 g/mol≈

51.5 g/mol

This means that you have

51.5g/mol×n=51.5g/mol

As you can see, you have

n=1.

This means that the empirical formula and the molecular formula are equivalent,

NH Cl.

2

6 0

3 years ago

Read 2 more answers

The modern periodic table can be divided into ____________and ________________.

The modern periodic table can be divided into and ____.