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3 years ago

Explain what the name carbohydrate might indicate about the chemical composition of sugars

2 answers:

6 0

The name carbohydrate indicate chemical composition of sugars, as carb means carbon and hydrate means hydrogen and oxygen.

Carbohydrate indicates the presence of carbon, hydrogen and oxygen of which sugar molecule is made up of.

Carbohydrate can be defined as naturally occuring molecules that is made of carbon, hydrogen and oxygen.

ELEN [110]3 years ago

3 0

Answer:

Carbohydrate is a biological macromolecule, which has a general molecular formula $C_{m} (H_{2} O)_{n}$ .

Technically, the name carbohydrates suggest that the molecules are the <u>hydrates of carbon</u>, composed of the elements hydrogen, oxygen, and carbon. This is because, the ratio of <u>hydrogen: oxygen in a carbohydrate molecule is 2:1, as in a water molecule.</u>

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I NEED HELP WITH THESE! PLEASEEE

cupoosta [38]

Answer:

have you interested sex then reply me I am from India

6 0

2 years ago

A 7.337 gram sample of chromium is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 9.595 g. Dete

Thepotemich [5.8K]

<h3>Answer:</h3>

Empirical formula is CrO

<h3>Explanation:</h3>

<u>We are given;</u>

Mass of sample of Chromium as 7.337 gram
Mass of the metal oxide formed as 9.595 g

We are required to determine the empirical formula of the metal oxide.

<h3>Step 1 ; Determine the mass of oxygen used </h3>

Mass of oxygen = Mass of the metal oxide - mass of the metal

= 9.595 g - 7.337 g

= 2.258 g

<h3>Step 2: Determine the moles of chromium and oxygen</h3>

Moles of chromium metal

Molar mass of chromium = 51.996 g/mol

Moles of Chromium = 7.337 g ÷ 51.996 g/mol

= 0.141 moles

Moles of oxygen

Molar mass of oxygen = 16.0 g/mol

Moles of Oxygen = 2.258 g ÷ 16.0 g/mol

= 0.141 moles

<h3>Step 3: Determine the simplest mole number ratio of Chromium to Oxygen</h3>

Mole ratio of Chromium to Oxygen

Cr : O

0.141 mol : 0.141 mol

1 : 1

Empirical formula is the simplest whole number ratio of elements in a compound.

Thus the empirical formula of the metal oxide is CrO

6 0

3 years ago

What weight of sodium formate must be added to 4.00L of 1.00 M formic acid to produce a buffer solution that has a pH of 3.50?

tester [92]

Answer:

156,4 g of sodium formate

Explanation:

The pka of the formic acid is 3,74. Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [A⁻] / [HA] <em>(1)</em>

Where A⁻ is the conjugate base (Formate) and HA is the formic acid.

4.00L of 1.00M formic acid contain:

4.00L × (1.00mol /L) = 4.00 moles

Replacing these moles, the desired pH and the pka value in (1):

3,50 = 3,74 log₁₀ [A⁻] / 4,00 moles

-0,24 = log₁₀ [A⁻] / 4,00 moles

0,575 = [A⁻] / 4,00 moles

<em>2,30 moles = [A⁻] </em>

That means you need 2,30 moles of formate (Sodium formate), to produce the desired buffer. As the molar mass of sodium formate is 68,01g/mol, the weight of sodium formate that must be added is:

2,30mol×(68,01g/mol) =<em> 156,4 g of sodium formate</em>.

I hope it helps!

7 0

3 years ago

Which of the following is true about fossils?

Agata [3.3K]

Answer:C

Explanation:

7 0

3 years ago

Read 2 more answers

Vishwanath had some money. he spent 3 upon 4 part of money to buy goods for his birthday,1 upon 5 part of money give to his sist

lord [1]

Answer:

The correct answer is - 800.

Explanation:

Given:

Total amount = ? or assume x

spend in buying birthday item = 3/4 of x

given to sister = 1/5 of x

remaining to mother = 40

solution:

the remaning amount = x- (3x/4+x/5) = 4=

=> x- 19x/20 = 40

=> x = 20*40

=> x = 800

thus, the correct answer is = 800

8 0

2 years ago