Answer:
Explanation:
Carbon (coke) burns in air to form carbon dioxide gas.
(i) C(s) + O2 ↑= CO2 ↑
Explanation:
Let us assume that the value of
= ![2.82 \times 10^{5} \times e^({\frac{-9835}{T}}) m^{6}/mol^{2}s](https://tex.z-dn.net/?f=2.82%20%5Ctimes%2010%5E%7B5%7D%20%5Ctimes%20e%5E%28%7B%5Cfrac%7B-9835%7D%7BT%7D%7D%29%20m%5E%7B6%7D%2Fmol%5E%7B2%7Ds)
Also at 1500 K,
= ![2.82 \times 10^{5} \times e^({\frac{-9835}{1500}}) m^{6}/mol^{2}s](https://tex.z-dn.net/?f=2.82%20%5Ctimes%2010%5E%7B5%7D%20%5Ctimes%20e%5E%28%7B%5Cfrac%7B-9835%7D%7B1500%7D%7D%29%20m%5E%7B6%7D%2Fmol%5E%7B2%7Ds)
![K_{r} = 400.613 m^{6}/mol^{2}s](https://tex.z-dn.net/?f=K_%7Br%7D%20%3D%20400.613%20m%5E%7B6%7D%2Fmol%5E%7B2%7Ds)
Relation between
and
is as follows.
![K_{p} = K_{c}RT](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20K_%7Bc%7DRT)
Putting the given values into the above formula as follows.
![K_{p} = K_{c}RT](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20K_%7Bc%7DRT)
![0.003691 = K_{c} \times 8.314 \times 1500](https://tex.z-dn.net/?f=0.003691%20%3D%20K_%7Bc%7D%20%5Ctimes%208.314%20%5Ctimes%201500)
![K_{c} = 2.9 \times 10^{-7}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%202.9%20%5Ctimes%2010%5E%7B-7%7D)
Also, ![K_{c} = \frac{K_{f}}{K_{r}}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cfrac%7BK_%7Bf%7D%7D%7BK_%7Br%7D%7D)
or, ![K_{f} = K_{c} \times K_{r}](https://tex.z-dn.net/?f=K_%7Bf%7D%20%3D%20K_%7Bc%7D%20%5Ctimes%20K_%7Br%7D)
= ![2.9 \times 10^{-7} \times 400.613](https://tex.z-dn.net/?f=2.9%20%5Ctimes%2010%5E%7B-7%7D%20%5Ctimes%20400.613)
= ![1.1617 \times 10^{-4} m^{6}/mol^{2}s](https://tex.z-dn.net/?f=1.1617%20%5Ctimes%2010%5E%7B-4%7D%20m%5E%7B6%7D%2Fmol%5E%7B2%7Ds)
Thus, we can conclude that the value of
is
.
Answer: its the first one buster
Answer:
2H+(aq) + 2OH-(aq) → 2H2O(l)
Explanation:
Step 1: The balanced equation
2HCl(aq)+Ca(OH)2(aq) → 2H2O(l)+CaCl2(aq)
This equation is balanced, we do not have the change any coefficients.
Step 2: The netionic equation
The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.
2H+(aq) + 2Cl-(aq) + Ca^2+(aq) + 2OH-(aq) → 2H2O(l) + Ca^2+(aq) + 2Cl-(aq)
After canceling those spectator ions in both side, look like this:
2H+(aq) + 2OH-(aq) → 2H2O(l)