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3 years ago

Describing the Functions of Organic Compounds

Chemistry

2 answers:

exis [7]3 years ago

7 0

Answer:

Lipids - used for long-term energy storage

Proteins - used for tissue repair and growth

Nucleic acids - used for storing and transmitting genetic information

Carbohydrates - used for energy

Explanation:

Both lipids and carbohydrates are used for energy storage. However, lipids are used for long-term storage and store twice as much energy as carbohydrates, while carbohydrates are used for short-term storage.

Proteins play many roles in our bodies. They are used for tissue repair and growth, metabolic reactions, and coordination of bodily functions. They also maintain proper pH and fluid balance.

Nucleic acids are macromolecules found in all cells and viruses used for storing and transmitting genetic information. Two main types of nucleic acids are DNA and RNA.

cupoosta [38]3 years ago

5 0

Answer:

Lipids: used for long-term energy storage
Nucleic acids: used for storing and transmitting genetic information
Protein: used for tissue repair and growth
Carbohydrates: used for energy

Explanation:

These terms simply have to be memorized, but understanding their structure can help you gain a better grasp of their functions. Lipids have fatty acid chains with lots of bonds, so they are high energy. Nucleic acids have pieces that can be rearranged into many combinations that can be read by certain structures. Proteins are composed of different building blocks with different properties. The sum of these properties is the function of the protein. Lastly, carbohydrates have compact monomers that are extremely easy to break apart into energy.

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Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?

Sindrei [870]

Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂ = 4 x 1 / 2

= 2 moles of Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of Mg(OH)₂ = n x mm

mass of Mg(OH)₂ = 58 x 2

= 116 g of Mg(OH)₂

hope this helps!

8 0

3 years ago

What type(s) of intermolecular forces are expected between ch3ch2ch2ch2ch2oh molecules?

notka56 [123]

Answer : Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

Explanation :

The given molecule is, $CH_3CH_2CH_2CH_2CH_2OH$

Three types of inter-molecular forces are present in this molecule which are Hydrogen-bonding, Dipole-dipole attraction and London-dispersion force.

Hydrogen-bonding : when the partial positive end of hydrogen is bonded with the partial negative end of another molecule like, oxygen, nitrogen, etc.

Dipole-dipole attraction : When the partial positively charged part of the molecule is interact with the partial negatively charged part of the molecule. For example : In case of HCl.

London-dispersion force : This force is present in all type of molecule whether it is a polar or non-polar, ionic or covalent. For example : In case of Br-Br , F-F, etc

Hydrogen-bonding is present between the oxygen and hydrogen molecule.

Dipole-dipole forces is present between the carbon and oxygen molecule.

London-dispersion forces is present between the carbon and carbon molecule.

5 0

3 years ago

Ep-15 why is carbon monoxide especially dangerous?

Rzqust [24]

Carbon monoxide is dangerous because it binds with hemoglobin in the blood.

Hemoglobin is made up of proteins that bind to iron atoms. The structure of the protein facilitates loose binding of oxygen. On other hand, Carbon monoxide binds very strongly to the iron in hemoglobin. Once carbon monoxide is bonded to hemoglobin, it is very difficult to release. This, eventually results in blood losing it its ability to transport oxygen. Hence, the person will suffocate. Due to this, CO is dangerous.

8 0

3 years ago

Calculate the molality of a 20.0% by mass ammonium sulfate (nh4)2so4 solution. the density of the solution is 1.117 g/ml.

olasank [31]

Hello!

We have the following data:

m1 (solute mass) = 20 % m/m
M1 (Molar mass of solute) (NH4)2 SO4 = ?
m2 (mass of the solvent) = ? (in Kg)

First we find the solute mass (m1), knowing that:

20% m/m = 20g/100mL

20 ------ 100 mL (0,1 L)
y g --------------- 1 L

y = 20/0,1
y = 200 g --> m1 = 200 g

Let's find Solute's Molar Mass, let's see:

M1 of (Nh4)2SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

We must find the volume of the solvent and therefore its mass (m2), let us see:

d = 1,117 g/mL
m = 200 g
v (volumen of solute) = ?

$d = \dfrac{m}{V} \to V = \dfrac{m}{d}$

$V = \dfrac{200\:\diagup\!\!\!\!g}{1,117\:\diagup\!\!\!\!g/mL} \to V = 179\:mL\:(volumen\:of\:solute)$

The solvent volume will be:

1000 -179 => V = 821 mL (volumen of disolvent)

If: 1 mL = 1g

Then the mass of the solvent is:

m2 (mass of the solvent) = 821 g → m2 (mass of the solvent) = 0,821 Kg

Now, we apply all the data found to the formula of Molality, let us see:

$\omega = \dfrac{m_1}{M_1*m_2}$

$\omega = \dfrac{200}{132*0,821}$

$\omega = \dfrac{200}{108,372}$

$\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark$

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Another way to find the answer:

We have the following data:

W (molality) = ? (in molal)
n (number of mols) = ?
m1 (solute mass) = 20 % m/m = 20g/100mL → (in g to 1L) = 200 g
m2 (disolvent mass) the remaining percentage, in the case: 80 % m/m = 800 g → m2 (disolvent mass) = 0,8 Kg
M1 (Molar mass of solute) (NH4)2 SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

Let's find the number of mols (n), let's see:

 $n = \dfrac{m_1}{M_1}$

$n = \dfrac{200}{132}$

$n \approx 1,5\:mol$

Now, we apply all the data found to the formula of Molality, let us see:

$\omega = \dfrac{n}{m_2}$

$\omega = \dfrac{1,5}{0,8}$

$
\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark$

I hope this helps. =)

7 0

3 years ago

An atom of chlorine has several valence electrons in its

RUDIKE [14]

7 valence electrons in an atom

7 0

3 years ago