All categories

3 years ago

Is Nb6+ a oxidizing agent?

Chemistry

2 answers:

Phantasy [73]3 years ago

7 0

Answer:

yes

Explanation:

because of high positive charge of Nb6+ delta G is more negative for Nb6+ as an oxidising agent♡

adelina 88 [10]3 years ago

5 0

Answer:

So Sn2+ is a reducing agent (oxidises itself to Sn4+ hence becoming stable) while Pb2+ is already stable so it neither undergoes oxidation nor reduction.

You might be interested in

Earthquakes , volcanoes mountains and oceans trenches are most closely associated with which plate boundary?

masya89 [10]

Answer:

continental plate boundary

8 0

2 years ago

Determine the electron geometry (eg) and molecular geometry (mg) of <img src="https://tex.z-dn.net/?f=CH_3%5E%2B" id="TexFormula

Yuri [45]

Answer : The correct option is, (e) eg = trigonal planar, mg = trigonal planar

Explanation :

Formula used :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is, $CH_3^+$

$\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3$

That means,

Bond pair = 3

Lone pair = 0

The number of electron pair are 3 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

Hence, the electron geometry (eg) and molecular geometry (mg) of $CH_3^+$ is, trigonal planar and trigonal planar respectively.

7 0

2 years ago

Which of the following statements correctly describes boyle's law

abruzzese [7]

<span>In the said law, the volume of a gas varies inversely with pressure. Boyle's law is one of the gas laws we have. According to this law, at a fixed amount of an ideal gas which is at constant temperature, the pressure and volume are inversely proportional with each other. <span>The variables are volume and pressure.</span></span>

3 0

3 years ago

GOOD MORNING GUYS☕☕☕☕

Vinvika [58]

Answer:

GOOD MORNING DIDI be happy

8 0

2 years ago

Read 2 more answers

Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o

elena-s [515]

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

Electronegativity values: Br = 2.8, Cl = 3

Difference = 3.0 -2.8 = 0.2

Therefore, the increasing order of polarity is

F2 = CS2 < BrCl < SCl2 < CF4

5 0

3 years ago