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AlexFokin [52]
3 years ago
6

2. A 1,100 kg car comes uniformly to a stop. If the vehicle is accelerating at -1.2 m/s ², which force is closest to the net for

ce acting on the vehicle? (8.6A) *
Physics
2 answers:
Andrew [12]3 years ago
7 0

Answer:

Since the car comes uniformly to a stop, the force that acts on the vehicle is the net force whose magnitude is equal to 1320 N.

Explanation:

The force acting on the vehicle is given:

F = ma

Where:

m: is the mass = 1100 kg

a: is the acceleration = -1.2 m/s²

We can find the magnitude of the net force:

F = ma = 1100 kg*1.2 m/s^{2} = 1320 N

Since the car comes uniformly to a stop, the force that acts on the vehicle is the net force calculated above.        

I hope it helps you!                                                

svetlana [45]3 years ago
3 0

Answer: its d because it said net force meaning the sum of the forces equaling to d

Explanation:

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Advocard [28]

Answer:

Be serious or else CEO of brainly will kick you out

3 0
3 years ago
A van accelerates from 4m/s to 20m/s in 8s. How far does it travel in this time?​
zubka84 [21]

Answer:

96 m

Explanation:

Given,

Initial velocity ( u ) = 4 m/s

Final velocity ( v ) = 20 m/s

Time ( t ) = 8 s

Let Acceleration be " a ".

Formula : -

a = ( v - u ) / t

a = ( 20 - 4 ) / 8

= 16 / 8

a = 2 m/s²

Let displacement be " s ".

Formula : -

s = ut + at² / 2

s = ( 4 ) ( 8 ) + ( 2 ) ( 8² ) / 2

= 32 + ( 2 ) ( 64 ) / 2

= 32 + ( 2 ) ( 32 )

= 32 + 64

s = 96 m

Therefore, it travels 96 m in time 8 s.

3 0
3 years ago
What is the direction of the force for a negative charge moving downward in a magnetic field pointing to the left?
velikii [3]

Answer: A

Out of the screen

Explanation:

Using right hand rule, the magnetic force is perpendicular to the plane form by the magnetic field of a charged particle and its speed. Which will be into the screen.

But the negative charged particle moves in the opposite direction of the positive charged particle. Therefore, the magnetic force direction will be out of the screen

5 0
3 years ago
A wave front has the form of a
podryga [215]
Your answer is "<span>surface of a sphere"

Hope this helps.</span>
3 0
3 years ago
Un cubo de madera de densidad 0.780 g/cm³ mide 11.2 cm en un lado. Cuando se coloca en agua, ¿qué altura del bloque flotará sobr
Stolb23 [73]

Answer:

2.464 cm above the water surface

Explanation:

Recall that for the cube to float, means that the volume of water displaced weights the same as the weight of the block.

We calculate the weight of the block multiplying its density (0.78 gr/cm^3) times its volume (11.2^3  cm^3):

weight of the block = 0.78 * 11.2^3  gr

Now the displaced water will have a volume equal to the base of the cube (11.2 cm^2) times the part of the cube (x) that is under water. Recall as well that the density of water is 1 gr/cm^3.

So the weight of the volume of water displaced is:

weight of water = 1 * 11.2^2 * x

we make both weight expressions equal each other for the floating requirement:

0.78 * 11.2^3 = 11.2^2 * x

then x = 0.78 * 11.2 cm = 8.736 cm

This "x" is the portion of the cube under water. Then to estimate what is left of the cube above water, we subtract it from the cube's height (11.2 cm) as follows:

11.2 cm - 8.736 cm = 2.464 cm

6 0
3 years ago
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