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DedPeter [7]
3 years ago
13

Nomenclature of calcium chloride​

Chemistry
2 answers:
Umnica [9.8K]3 years ago
7 0

Answer:

CHEBI:3312 - calcium dichloride

Explanation:

Calcium chloride is an inorganic compound, a salt with the chemical formula CaCl2.

ELEN [110]3 years ago
5 0

Answer:

CHEBI:3312 - Calcium dichloride

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A 0.0884 M solution of a weak base has a pH of 11.79. What is the identity of the weak base?Weak Base KbEthylamine (CH3CH2NH2) 4
iVinArrow [24]

Answer:

The base must be ethylamine.

Explanation:

The pH of solution of a weak base gives us an idea about the Kb of the base.

pOH=14-pH

pOH=14-11.79=2.21

pOH=-log[OH^{-}]

[OH^{-}]=0.0062M

The relation between Kb and hydroxide ion concentration is:

Kb=\frac{[OH^{-}]^{2}}{[base]}

Kb=\frac{0.0062X0.0062}{0.0884}=4.34X10^{-4}

Thus the weak base must be ethylamine.

7 0
3 years ago
What is the net electric charge of an ionic compound?
BARSIC [14]

Ionic compounds contain both cations and anions in a ratio that results in no net electrical charge

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3 years ago
A 15.0-L rigid container was charged with 0.500 atm of kryp‑ ton gas and 1.50 atm of chlorine gas at 350.8C. The krypton and chl
Alecsey [184]

Answer: 32.94 g

Explanation: It's stoichiometry problem so balanced equation is required. The balanced equation is given below:

Kr+2Cl_2\rightarrow KrCl_4

From the balanced equation, krypton and chlorine react in 1:2 mol ratio. We will calculate the moles of each reactant gas using ideal gas law equation(PV = nRT) and then using mol ratio the limiting reactant is figured out that helps to calculate the amount of the product formed.

for Krypton, P = 0.500 atm and for chlorine, P = 1.50 atm

V = 15.0 L

T = 350.8 + 273 = 623.8 K

For krypton, n=\frac{0.500*15.0}{0.0821*623.8}

n = 0.146 moles

for chlorine, n=\frac{1.50*15.0}{0.0821*623.8}

n = 0.439

From the mole ratio, 1 mol of krypton reacts with 2 moles of chlorine. So 0.146 moles of krypton will react with 2 x 0.146 = 0.292 moles of chlorine.

Since 0.439 moles of chlorine are available, it is present in excess and hence the limiting reactant is krypton.

So, the amount of product formed is calculated from moles of krypton.

Molar mass of krypton tetrachloride is 225.61 gram per mol.

There is 1:1 mol ratio between krypton and krypton tetrachloride.

0.146molKr(\frac{1molKrCl_4}{molKr})(\frac{225.61gKrCl_4}{1molKrCl_4})

= 32.94 g of KrCl_4

So, 32.94 g of the product will form.

5 0
4 years ago
How many molecules are in 5.40 mol of CO2?
Elena L [17]

Answer:

1 mol compund has 6.023x10 to the power of 24

so 5.40 mol has (5.40 x 6.023 x 10 to the power of 23)

Explanation:

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3 years ago
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