1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ch4aika [34]
3 years ago
13

I wish to have a computer whose machine-level instructions are all 32 bits each. If I want to have all instructions of the form

mov R1, R2 where R1 and R2 are registers. What is the maximum number of instructions that my machine can have, if my computer needs to have at least 1000 different registers referenced in the instructions?
Engineering
1 answer:
melisa1 [442]3 years ago
4 0

Answer:

Maximum number that can be represented by 13 bits  is 8192 Instructions

Explanation:

number of instructions = 1000

number of bits = log(1000) x number of register

                          = 6 bits

Since the complete instruction must have 32 bits, then

remaining number of bits = 32 - 6 = 236

number of registers in instruction = 2

number of bits per register = 26/2 = 13

Maximum number that can be represented by 13 bits = 2^{n}

                       = 2¹³ = 8192

You might be interested in
I will Brainlist<br> "Burning and Inch". Describe this measurement.
MAVERICK [17]

Answer:

what measurement

Explanation:

8 0
3 years ago
Read 2 more answers
How many trips would one rubber-tired Herrywampus have to make to backfill a space with a geometrical volume of 5400 cubic yard?
nikklg [1K]

Answer:

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

Explanation:

a) By volume.

The shrinkage factor is:

\frac{5400cu-yd}{1-0.25} =7200cu-yd

The volume at loose is:

V_{loose} =V_{bank} (1+swell-factor)=7200(1+0.2)=8640cu-yd

If the Herrywampus has a capacity of 30 cubic yard:

\frac{8640cu-yd}{30cu-yd/trip} =288trip

b) By weight

The swell factor in terms of percent swell is equal to:

pounds-per-cubic-yard-loose=\frac{pounds-per-cubic-yard-bank}{\frac{percent-swell}{100}+1 }

pounds-per-cubic-yard-loose=\frac{3000}{\frac{20}{100} +1} =2500lb/cu-yd

The weight of backfill is:

8640cu-yd*2500\frac{lb}{cu-yd} *\frac{1ton}{2000lb} =10800ton

The Herrywampus has a capacity of 40 ton:

\frac{10800}{40ton/trip} =270trip

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

8 0
3 years ago
The correct name for a “shooting star” is a:
nirvana33 [79]

Answer:

There is no "correct" name, but the scientific name could be meteorite.

8 0
3 years ago
Read 2 more answers
The power supply converts the wall outlet AC power into DC power. T or F
Alika [10]

Answer:

True

Explanation:

All computer parts require DC power to operate, and wall outlets provide AC Power.

7 0
3 years ago
An automotive fuel cell consumes fuel at a rate of 28m3/h and delivers 80kW of power to the wheels. If the hydrogen fuel has a h
EastWind [94]

Answer:

The efficiency of this fuel cell is 80.69 percent.

Explanation:

From Physics we define the efficiency of the automotive fuel cell (\eta), dimensionless, as:

\eta = \frac{\dot W_{out}}{\dot W_{in}} (Eq. 1)

Where:

\dot W_{in} - Maximum power possible from hydrogen flow, measured in kilowatts.

\dot W_{out} - Output power of the automotive fuel cell, measured in kilowatts.

The maximum power possible from hydrogen flow is:

\dot W_{in} = \dot V\cdot \rho \cdot L_{c} (Eq. 2)

Where:

\dot V - Volume flow rate, measured in cubic meters per second.

\rho - Density of hydrogen, measured in kilograms per cubic meter.

L_{c} - Heating value of hydrogen, measured in kilojoules per kilogram.

If we know that \dot V = \frac{28}{3600}\,\frac{m^{3}}{s}, \rho = 0.0899\,\frac{kg}{m^{3}}, L_{c} = 141790\,\frac{kJ}{kg} and \dot W_{out} = 80\,kW, then the efficiency of this fuel cell is:

(Eq. 1)

\dot W_{in} = \left(\frac{28}{3600}\,\frac{m^{3}}{s}\right)\cdot \left(0.0899\,\frac{kg}{m^{3}} \right)\cdot \left(141790\,\frac{kJ}{kg} \right)

\dot W_{in} = 99.143\,kW

(Eq. 2)

\eta = \frac{80\,kW}{99.143\,kW}

\eta = 0.807

The efficiency of this fuel cell is 80.69 percent.

3 0
3 years ago
Other questions:
  • The uniform dresser has a weight of 90 lb and rests on a tile floor for which the coefficient of static friction is 0.25. If the
    6·1 answer
  • Which of the following is not true about Machine Learning?Machine Learning was inspired by the learning process of human beings.
    11·1 answer
  • Air enters a compressor operating at steady state with pressure of 90 kPa, at a temperature of 350 K, and a volumetric flow rate
    13·1 answer
  • Define the difference between elastic and plastic deformation in terms of the effect on the crystal lattice structure.
    5·1 answer
  • Assignment 1: Structural Design of Rectangular Reinforced Concrete Beams for Bending
    6·1 answer
  • Create a document that includes a constructor function named Company in the document head area. Include four properties in the C
    7·1 answer
  • What are significant figures​
    13·1 answer
  • Which of the following best describes the role of engineers
    12·1 answer
  • For Laminar flow conditions, what size pipe will deliver 90 gpm of medium oil at 40°F (υ = 6.55 * 10^‐5)?
    12·1 answer
  • How do we infer that there is
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!