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irina [24]
3 years ago
15

Which elements listed is likely to be the most reactive

Chemistry
2 answers:
Sloan [31]3 years ago
6 0

Answer:

I'm not sure please list the elements respond with the list and I will give the answer.

marusya05 [52]3 years ago
3 0

Answer:

fluorine

Explanation:

i took the test on edg

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How many atoms are in 162.0 g of magnesium? ​
lidiya [134]

Answer:

3,938.22

Explanation:

(correct me if I'm wrong)

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3 years ago
List the types of properties in science
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Cells, antibodies…



jk don’t actually try this, be more specific about the question?
8 0
3 years ago
What's the answer to this and why? need a answer asap​
ioda

Answer:

Aluminum

Explanation:

Because there's no other element that has this exact electron configuration

4 0
3 years ago
A research team has just discovered a new element called Likhitium. Now they need to determine the average atomic mass in order
earnstyle [38]

The question is incomplete, the complete question is shown in the image attached to this answer.

Answer:

139.13

Explanation:

The average atomic mass of the element Likhitium is the sum of the relative abundance of all the isotopes of Likhitium.

We obtain the relative atomic mass of Likhitium as follows;

(44.7/100 * 138) + (52.3/100 * 139) + (0.5/100 * 140) + (2.5/100 * 141)

61.7 + 73.2 + 0.7 + 3.53 = 139.13

Hence the relative abundance of Likhitium is 139.13

6 0
3 years ago
Consider 100.0 g samples of two different compounds consisting only of vanadium and oxygen. one compound contains 61.4 g of vana
xxMikexx [17]

Answer:

2:1

Explanation:

The Law of Multiple Proportions states that when two elements A and B combine to form two or more compounds, the masses of B that combine with a given mass of A are in the ratios of small whole numbers.

That is, if one compound has a ratio r₁ and the other has a ratio r₂, the ratio of the ratios r is in small whole numbers.

1. Compound 1

Mass of O = 100.0 - 61.4 = 38.6 g

r_{1} = \dfrac{\text{mass of O}}{\text{mass of V}} = \dfrac{ 38.6}{61.4} = 0.6287

2. Compound 2

Mass of O = 100.0 - 76.1 = 23.9 g

r_{2} = \dfrac{ 23.9}{76.1} = 0.3141

3. Ratio of the ratios

r = \dfrac{r_{1}}{r_{2}} = \dfrac{ 0.6287}{0.3141} = \dfrac{2.00}{1} \approx 2\\\\\text{The relative amounts of O per gram of V are in the ratio }\boxed{\mathbf{\dfrac{2}{1}}}

For example. the compounds might be VO₂ and VO.

7 0
3 years ago
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