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3 years ago

Describe an Earth system that recycles resources in a way that is similar to how a spacecraft recycles resources.

Physics

2 answers:

FinnZ [79.3K]3 years ago

6 0

Different trash systems

weqwewe [10]3 years ago

3 0

Answer:

the differenced trash

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Missy Diwater the former platform diver for the Ringling Brother's circus had a kinetic energy of 15000 j just to prior to hitti

tatiyna

Missy's velocity is 24.5 m/s

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. Mathematically, it is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its velocity

In this problem, we know:

K = 15000 J is Missy's kinetic energy

m = 50 kg is her mass

Solving for v, we find her velocity:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(15000)}{50}}=24.5 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

4 0

3 years ago

Newton’s law of cooling states that dx dt = −k(x−A) where x is the temperature,t is time, A is the ambient temperature, and k &g

lys-0071 [83]

Answer:

a) $X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}$

b)Does not affect the long term.

Explanation:

Given that

$\dfrac{dx}{dt}=-k(x-A)$

A = A0 cos(ωt)

$\dfrac{dx}{dt}=-k(x-A_o cos(\omega t))$

$\dfrac{dx}{dt}+kx=kA_o cos(\omega t)$

This is linear equation so integration factor ,I

$I=e^{\int kdt}$

$I=e^{kt}$

Now by using linear equation property

$e^{kt} X=\int e^{kt} kA_o cos(\omega t) dt +C$

$e^{kt} X= kA_o \dfrac{e^{kt}}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+C$

$X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}$

at t= 0

$X(0)=\dfrac{k^2A_o}{\omega^2+k^2}+C$

$X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+e^{-kt}\times \left ( X(0)-\dfrac{k^2A_o}{\omega^2+k^2} \right )$

So the initial condition does not affect the long term.

5 0

3 years ago

A 1200-kg ore cart is rolling at 10.8 m/s across a flat friction-free surface. a crane suddenly drops of ore vertically into the

Andre45 [30]

The value of the final speed depends on the mass of the ore.

Let's call m the mass of the ore. We can solve the exercise by requiring the conservation of momentum, which must be the same before and after the ore is loaded.

Initially, there is only the cart, so the momentum is
$p=Mv=(1200 kg)(10.8 m/s)=12960 kg m/s$
After the ore is loaded, the new mass will be (1200 kg+m), and the new speed is $v_f$ . The momentum p is conserved, so it is still 12960 kg m/s. Therefore, we have
$p=12960 kg m/s =(1200 kg+m)v_f$
and so the final speed is
$v_f = \frac{12960 kg m/s}{1200 kg +m}$

5 0

3 years ago

1. Given a list of atomic model descriptions:

laiz [17]

Answer: A: electron shells outside a central nucleus

B: hard, indivisible sphere

C: mostly empty space

Which list of atomic model descriptions represents

the order of historical development from the earliest

to most recent?

Explanation:

8 0

3 years ago

Preston tossed a red ball upward and it reaches a maximum height of 3.0. What is the final velocity when it returns to prestons

Leokris [45]

That will depend on the units of the 3.0. We need to know if it's 3 feet, 3 yards, 3 meters, or 3 miles. Each one will have a different answer.

5 0

2 years ago