Answer:
d = 6.43 cm
Explanation:
Given:
- Speed resistance coefficient in silicon n = 3.50
- Memory takes processing time t_p = 0.50 ns
- Information is to be obtained within T = 2.0 ns
Find:
- What is the maximum distance the memory unit can be from the central processing unit?
Solution:
- The amount of time taken for information pulse to travel to memory unit:
t_m = T - t_p
t_m = 2.0 - 0.5 = 1.5 ns
- We will use a basic relationship for distance traveled with respect to speed of light and time:
d = V*t_m
- Where speed of light in silicon medium is given by:
V = c / n
- Hence, d = c*t_m / n
-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50
d = 0.129 m 12.9 cm
- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm
To calculate the work, we use:
W = PΔV
W = 10(0.4-0.01)
W = 3.9 L*atm
W = 3.9 * 101.3
W = 395.07 Joules
Answer:
Explanation:
An acid has H as the metal as in HCl
A base has OH as the nonmetal. (so Ca(OH)^2 is a base)
A salt has neither.
Answer:
a.) 2.66 seconds for 79.2 km/h and 1.82 seconds for 47.8 km/h
b.)-4.13 m/s2 for 79.2 km/h and -3.63 m/s2 for 47.8 km/h
Explanation:
Now for (a)
time = velocity/distance
for velocity = 79.2 km/h and distance 0.0586 km
t = (0.0586/79.2)*3600
t = 2.66 seconds (Please note that multiplication with 3600 is to convert hours into seconds)
for velocity 47.8 km/h and distance 0.0242 km
t = (0.0242/47.8)*3600
t = 1.82 seconds
Now for (b)
2as = vf2-vi2
so,
2a(58.6) = -(79.2*1000/3600)^2 (Please note that multiplication and division with 1000 and 3600 respectively is to convert speed unit from km/h to m/s)
a = -4.13 m/s2 for 58.6 m
and
2a(24.2) = -(47.8*1000/3600)^2
a = -3.63 m/s2 for 24.2 m.
Please note that "-" sign express the deceleration.
