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olganol [36]
3 years ago
8

This equation shows the reaction that occurs when calcium carbonate

Physics
2 answers:
velikii [3]3 years ago
4 0

Answer:

endothermic

Explanation:

this is only for the daily thing

yarga [219]3 years ago
3 0

Answer:

a. endothermic

Explanation:

The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.

  • Endothermic changes involves absorption of heat from the surrounding.
  • The surrounding becomes colder at the end of the reaction.
  • When heat is on the reactant side, it suggests a reaction that requires a considerable input of energy.
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In a particular case of Compton scattering, a photon collides with a free electron and scatters backwards. The wavelength after
mafiozo [28]

Answer:

hence initial wavelength is \lambda =4.86\times10^{-12}m

Explanation:

shift in wavelength due to compton effect is given by

\lambda ^{'}-\lambda =\frac{h}{m_{e}c}\times(1-cos\theta )

λ' = the wavelength after scattering

λ= initial wave length

h= planks constant

m_{e}= electron rest mass

c= speed of light

θ= scattering angle = 180°

compton wavelength is

\frac{h}{m_{e}c}= 2.43\times10^{-12}m

\lambda '-\lambda =2.43\times10^{-12}\times(1-cos\theta )

\lambda '-\lambda =2.43\times10^{-12}\times(1+1 )  ( put cos 180°=-1)

also given λ'=2λ

putting values and solving we get

\lambda =4.86\times10^{-12}m

hence initial wavelength is \lambda =4.86\times10^{-12}m

4 0
4 years ago
What is the 3d model of oxygen molecule​
Diano4ka-milaya [45]

Answer:

the one that looks lik 0=0

Explanation:

3 0
4 years ago
At time t = 0 an elevator starts moving upward from the ground at a constant speed vo. At a later time t = T1 = 2.35s a marble i
PilotLPTM [1.2K]

Answer:

\frac{v_o^2}{19.62} + 2.35v_o

Explanation:

The marble released through the trap door inside the elevator going upward at a speed vo would have an upward velocity of vo, but begins to experience a downward acceleration g = 9.81m/s^2. This is essentially same as throwing the marble up at a speed of vo. We can solve for the greatest height using the law of energy conservation.

When the marble is traveling up, its potential energy is converted to kinetic energy:

E_p = E_k

mgh = mv_o^2/2

where m is the marble mass and h is the vertical distance traveled from the releasing point to the maximum height.

We can divide both sides by m

gh = v_o^2/2

h = \frac{v_o^2}{2g} = \frac{v_0^2}{2*9.81} = \frac{v_0^2}{19.62}

This is only partial of the height from the ground. To find the total height we need to add the height from the ground to the release point, which is the distance traveled by the elevator within time t = 2.35s at speed vo

\frac{v_o^2}{19.62} + 2.35v_o

Plug in the value for vo and we can calculate the maximum height

6 0
4 years ago
Which is an example of sliding friction?
stepan [7]

Answer:

You rubbing your hands together

Your hands are sliding against each other

5 0
3 years ago
Gold is the most ductile of all metals. For example, one gram of gold can be drawn into a wire 2.05 km long. The density of gold
arsen [322]

Answer:

Resistance of gold wire, R=1977 \times 10^3 ohm

Explanation:

In this question we have given

Density of gold, d=19.3\times 10^3 \frac{kg}{m^3}

resistivity of gold, r=2.44\times 10^{-8} ohm.m

Length of wire, L= 2.05 km

Temperature, T= 20^oC

We know that relation between volume and density is given as

Density= \frac{mass}{Volume}

Therefore, volume occupied by one gram gold is given as,

V=\frac{.001 kg}{19.3\times 10^3 Kg m^{-3}} = 5.181\times 10^{-8} m^3.........(1)

We Know that Volume of gold wire which is cylindrical in shape is given by following formula

V=\pi \times r^2 \times L......(2)

Here,

A= \pi \times r^2...........(3)

here A is the cross sectional area of cylendrical gold wire  

From equation 2 and 3

we got

V=A \times L...............(4)

on comparing equation 1 and equation 4, we got,

A \times L=5.181\times 10^{-8} m^3

A=\frac{5.181\times 10^{-8} m^3}{2050 m}

A=2.53\times 10^{-11}m^2

we know that resistance and resistivity are related by following formula,

Resistance = resistivity\times \frac{L}{A}................(5)

Put values of resistivity, A and L in equation 5, we got

R = \frac{2.44 \times 10^{-8} ohm.m \times 2050 m}{2.53\times 10^{-11} m^2}

R=1977 \times 10^3 ohm

Therefore resistance of gold wire, R=1977 \times 10^3 ohm

7 0
3 years ago
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