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3 years ago

Which is NOT a way to stay safe from static electricity?

Physics

1 answer:

Thepotemich [5.8K]3 years ago

7 0

a metal spike in an airport runway

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What type of metal are conducting wires most often made of?<br><br> #16

docker41 [41]

Answer:

here

Explanation:

Copper is commonly used as an effective conductor in household appliances and in electrical equipment in general. Because of its low cost, most wires are copper-plated. You will often find electromagnet cores normally wrapped with copper wire

3 0

2 years ago

What are the two factors that determine the amount of gravitational force between two objects?

melisa1 [442]

Answer:

The mass of the objects

Distance between the objects

Explanation:

The two factors that determines the amount of gravitational force between two objects is the mass of the objects and the distance between them.

Gravitational force of attraction is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between them. This is the postulate of the newton's law of universal gravitation.

Mathematically:

F = $\frac{Gm_{1}m_{2} }{r^{2} }$

m is the mass

r is the distance

G is the universal gravitation constant

6 0

3 years ago

One of the most effective ways to evaluate data is to try to replicate it.

zubka84 [21]

I believe the answer is False

6 0

3 years ago

If a car accelerates uniformly from rest to 15 meters

Talja [164]

Answer:

1.125m/s^2

Explanation:

Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically

v^2= u^2+2as

Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.

a = ?

u = 0m/s

v = 15m/s

s = 100m

Substituting the values into the formula above

v^2= u^2+2as

15^2=0^2+2×a×100

225= 0+200a

225= 200a

Divide both sides by 200

225/200 = 200a/200

a= 1.125m/s^2

Hence the acceleration of the car is 1.125m/s^2.

Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s

8 0

3 years ago

Read 2 more answers

Two flat 4.0 cm × 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite ea

Olenka [21]

Answer:

$q =1.07 \times 10^{-7}\ C$

Explanation:

given.

Two flat 4.0 cm × 4.0 cm electrodes carrying equal charge

space between the charges = 2 mm

Electric field strength = 7.6 x 10⁶ N/C

ε ₀ = 8.85 × 10⁻¹² C²/N · m²

magnitude of charge =?

Electric field strength between to two plates

$E = \dfrac{q}{A\epsilon_0}$

$q = E A \epsilon_0$

$q = 7.6 \times 10^6 \times 0.04 \times 0.04 \times 8.85 \times 10^{-12}$

$q =1.07 \times 10^{-7}\ C$

7 0

4 years ago