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grandymaker [24]
3 years ago
15

6) 3.2 grams of sodium chloride is dissolved to make 0.25 liters of solution. Hint Convert grams to moles first! Molar mass of N

aCl is 58.5 g/mol​
Chemistry
1 answer:
otez555 [7]3 years ago
5 0

Which solution is the least concentrated?

O 2 moles of solute dissolved in 4 liters of solution

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Which Statements below are true?
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A. If motion starts and stops at the same location, then the displacment is zero.

D. Distance is always greater than or equal to the magnitutde of the displacement.

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Write a word equation for the chemical reaction.<br><br> I’ll brainlist.
Alex

Answer:

potassium hydroxide + sulfuric acid → potassium sulfate + water.

Explanation:

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5 0
3 years ago
Taryn has a 90-gram sample of ethanol, which has a specific heat of
Angelina_Jolie [31]
35 Celsius minus the average 20 Celsius.  going to be  15. let me know if u need anything else.
7 0
3 years ago
Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl
tensa zangetsu [6.8K]

Answer:

[SO_2Cl_2] = 0.09983 M

Explanation:

Write the balance chemical equation ,

SO_2Cl_2((g) = SO_2(g) + Cl_2(g)

initial concenration of SO_2Cl_2((g)  =0.1M

lets assume that degree of dissociation=\alpha

concenration of each component at equilibrium:

[SO_2Cl_2] = 0.1-0.1\alpha

[SO_2] = 0.1\alpha

[Cl_2] = 0.1\alpha

Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}

Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}

as \alpha is very small then we can neglect  1-\alpha

therefore ,

Kc ={0.1\alpha \times \alpha}

\alpha =\sqrt{\frac{Kc}{0.1}}

\alpha = 1.73 \times 10^{-3}

Eqilibrium concenration of [SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173

[SO_2Cl_2] = 0.09983 M

4 0
3 years ago
The formula of nitrobenzene is c6h5no2. the molecular weight of this compound is __________ amu.
mafiozo [28]

The molecular weight of a given compound would simply the sum of the molar weights of each component.

 

The molar masses of the elements are:

C = 12 amu

H = 1 amu

N = 14 amu

O = 16 amu

where 1 amu = 1 g / mol

 

Since there are 6 C, 5 H, 1 N and 2 O, therefore the total molecular weight is:

molecular weight = 6 (12 amu) + 5 (1 amu) + 1 (14 amu) + 2 (16 amu)

molecular weight = 123 amu

 

Therefore the molecular weight of nitrobenzene is 123 amu or which is exactly equivalent to 123 g / mol.

4 0
3 years ago
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