with what?..................
Answer:
Oxidizing agent - CrO4^2-
Reducing agent- N2O
Explanation:
Let us look at the equation closely;
CrO4^2- (aq) + 3N2O(g) ------------> Cr^3+ (aq) + 3NO(g) [acidic]
The reduction half equation is;
CrO4^2- (aq) + 3e -------->Cr^3+ (aq)
Oxidation half equation is;
3N2O(g) ------>3 NO(g) +3 e
Note that the oxidizing agent participates in the reduction half equation while the reducing agent participates in the oxidation half equation as seen above.
5
mL acetic acid
95
mL water
Explanation:
Since
5
%
of the vinegar, by volume, is acetic acid, and we have
100
mL of vinegar, we have
5
mL of vinegar.
Similarly, we have
100
%
−
5
%
=
95
%
being water, so we have
95
mL of water.
I think the correct answer from the choices listed above is the second option. When two hydrogen atoms enter the ETS as part of either NADH or FADH2, the two hydrogen atoms are split into two H+ and two electrons. Hope this answers the questions.
