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Alexus [3.1K]
3 years ago
13

An exoplanetary system has two known planets. Planet X orbits in 290 days and Planet Y orbits in 145 days. Which planet is close

st to its host star? If the star has the same mass as the Sun, what is the semi-major axis of the orbits for Planets X and Y?
Physics
1 answer:
satela [25.4K]3 years ago
6 0

Answer:

Planet Y

Rx = 1.587 Ry

Explanation:

Tx = 290 days

Ty = 145 days

Let the semi major axis of planet X is Rx and of plant Y is Ry.

According to the Kepler's third law of planetary motion

\frac{T_{x}^{2}}{T_{y}^{2}}=\frac{R_{x}^{3}}{R_{y}^{3}}

\frac{290^{2}}{145^{2}}=\frac{R_{x}^{3}}{R_{y}^{3}}

4=\frac{R_{x}^{3}}{R_{y}^{3}}

1.587=\frac{R_{x}}{R_{y}}

Rx = 1.587 Ry

So, planet Y is closest to star.

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Would a bottleneck event of the plants in an area from the video at the top of this page result in the need for primary or secon
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7 0
2 years ago
A car moved 120km to the north. what is its displacement?
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5 0
3 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
stira [4]

Answer:

i) 24.5 m/s

ii) 30,656 m

iii) 89,344 m

Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

El tiempo en caída libre = 2.5 s

De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

t = Tiempo de caída libre = 2.5 s

Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

s = u · t + 1/2 · g · t²

= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m

iii) La altura restante = 120 - 30.656 = 89.344 m.

6 0
3 years ago
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