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Alexus [3.1K]
4 years ago
13

An exoplanetary system has two known planets. Planet X orbits in 290 days and Planet Y orbits in 145 days. Which planet is close

st to its host star? If the star has the same mass as the Sun, what is the semi-major axis of the orbits for Planets X and Y?
Physics
1 answer:
satela [25.4K]4 years ago
6 0

Answer:

Planet Y

Rx = 1.587 Ry

Explanation:

Tx = 290 days

Ty = 145 days

Let the semi major axis of planet X is Rx and of plant Y is Ry.

According to the Kepler's third law of planetary motion

\frac{T_{x}^{2}}{T_{y}^{2}}=\frac{R_{x}^{3}}{R_{y}^{3}}

\frac{290^{2}}{145^{2}}=\frac{R_{x}^{3}}{R_{y}^{3}}

4=\frac{R_{x}^{3}}{R_{y}^{3}}

1.587=\frac{R_{x}}{R_{y}}

Rx = 1.587 Ry

So, planet Y is closest to star.

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Answer:48 V

Explanation:

Given

Three charged particle with charge

q_1=50\ nC at y=6\ m

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q_3=70\ nC at y=-6\ m

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d_1=\sqrt{6^2+8^2}

d_1=\sqrt{36+64}

d_1=10\ m

similarly d_2=8-(-4)

d_2=12\ m

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d_3=\sqrt{36+64}

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Potential at x=8\ m is

V_{net}=\frac{kq_1}{d_1}+\frac{kq_2}{d_2}+\frac{kq_3}{d_3}

V_{net}=k[\frac{q_1}{d_1}+\frac{q_2}{d_2}+\frac{q_3}{d_3}]

V_{net}=9\times 10^9[\frac{50}{10}-\frac{80}{12}+\frac{70}{10}]\times 10^{-9}

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5 0
3 years ago
If a 20 N block experiences a force of kinetic friction of 8.0 N
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The coefficient of kinetic friction (μ) between the block and the table is 0.4.

<h3>What is kinetic friction?</h3>

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μ = ff/N

μ = 8/20

μ = 0.4

Thus, the coefficient of kinetic friction (μ) between the block and the table is 0.4.

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How is newtons law of motion used for testing the safety of automobile
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