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Alex787 [66]
3 years ago
7

The temperature on a distant, undiscovered planet is expressed in degrees B. For example, water boils at 180 ∘ B and freezes at

50 ∘ B . If it is 31 ∘ C on Earth, what would that temperature be in terms of degrees B?
Chemistry
1 answer:
marin [14]3 years ago
5 0

Answer:

40.3∘C

Explanation:

At planet B;

Water boils = 180∘C

Water freezes = 50∘C

In this planet the temperature difference = 180 - 50 = 130 compared to earth where the temperature difference is; 100 - 0 = 100

This means;

130 ∘C = 100 ∘C

x ∘C = 31 ∘C

x = 31 * 130 / 100

x = 40.3∘C

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Question 5
pantera1 [17]

Answer: The coefficient for the diatomic oxygen (O2) is 3.

Explanation:

To know the coefficient for the diatomic Oxygen, we need to balance the equation.

Fe + O2 ------->   Fe2O3

LHS of the equation; Fe =  1    , O2 = 1

RHS of the equation; Fe = 2 ,  O = 3

∴ Multiply 'Fe' on the LHS of the equation by 4 and O2 by 3

   Doing that will give the balance equation which is;

   4 Fe +  3 O2  --------> 2 Fe2O3

The coefficient for the diatomic oxygen (O2) as seen from the equation is 3.

7 0
3 years ago
IS THIS A BALANCED EQUATION <br> MgCl2 + Na2O -- &gt; MgO + 2 NaCl
Dmitriy789 [7]
Yes, this is balanced. Each part of the substance (like Mg) has the same number on both sides.

Hope this helps you:)
8 0
3 years ago
Which of the is an example of climate???<br> Help pls?
n200080 [17]
The first one, my friend
4 0
3 years ago
Read 2 more answers
How do i calculate the mass of CO2 emitted per Kj of heat produced in a combustion reaction?
Alexxandr [17]
 methanol:

1 mole CH3 OH --> produces --> 1 mole CO2 

1 mole CO2 has a molar mass of 44.01 gh/mole
 
your set up is:
(44.01 g CO2) / -726.5kJ = 0.06058g

your answer 0.06058 grams of CO2 produced per kJ released.
6 0
4 years ago
What are the empirical and molecular formulas of a hydrocarbon if combustion of 2.10 g of the compound yields 6.59 g co2 and 2.7
mariarad [96]

 The  empirical  formula    of hydrocarbon is  CH2

The  molecular formula  of the  hydrocarbon is  C6H12


    <u><em>Explanation</em></u>

Hydrocarbon  is  made up  of carbon and hydrogen


<h3><u><em> </em></u>Empirical formula  calculation</h3>

 Step 1:  find  the  moles   CO2  and  H2O

moles =mass/molar mass

moles   of CO2 =  6.59 g/ 44 g/mol = 0.15 moles

moles of H2O = 2.70 g / 18 g/mol =  0.15  moles

Step 2: Find the moles  ratio  of Co2:H2O  by diving  each mole by smallest mole(0.15)

that  is  for  CO2 = 0.15/0.15  =1

              For H2O = 0.15/0.15 =1

therefore  the mole ratio  of Co2 : H2O = 1:1  which  implies that 1 mole of Co2  and 1  mole of H2O is  formed  during combustion reaction.


From the  the law of mass conservation the number  of atoms in reactant side  must  be equal to  number of  atoms  in product side

therefore  since  there 1 atom  of C  in product side there  must be 1 atom of C  in reactant  side.

In addition  there is 2 H atom in product  side  which should be the  same  in reactant side.  

From information above the empirical formula is therefore = CH2


Molecular formula  calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n =  84 g/mol

n = 6

multiply the  each subscript  in CH2  by  6

 Therefore the molecular formula = C6H12




5 0
3 years ago
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