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Crank
2 years ago
8

2: Assume we have created a packet-switched internet. Using the TCP/IP protocol suite, we

Physics
1 answer:
yaroslaw [1]2 years ago
3 0

Answer:

Shown below as 'The advantage is that the router will always choose the faster route to send the packet and each connection is independent.'

Explanation:

The advantage is that the router will always choose the faster route to send the packet and each connection is independent.

Hope this helps!

Kind regards

Farah Syed

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to start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 53.0° above the ho
kap26 [50]
So this is easy to calculate when you split the velocity into x and y components. The x component is going to equal cos(53) * 290 and the y component is going to equal sin(53)*290.

The x location therefore is 290*cos(53)*35 = 6108.4m

The y location needs to factor in the downwards acceleration of gravity too, which is 9.81m/s^2. We need the equation dist. = V initial*time + 0.5*acceleration*time^2.

This gives us d=290*sin(53)*35 + (0.5*-9.81*35^2)=2097.5m

So your (x,y) coordinates equals (6108.4, 2097.5)
5 0
3 years ago
Two capacitors of capacitances 25 µF and 50 µF are connected in series with a 33-V battery. How much energy is stored in the 25-
torisob [31]

Answer:

6.05×10⁻³ J

Explanation:

Note: Two capacitors connected in series behaves like two resistors connected in parallel.

Using

1/Ct = 1/C1+1/C2

Ct = (C1×C2)/(C1+C2)............................ Equation 1

Where Ct = combined capacitance of the two capacitor, C1 = Capacitance of the first capacitor, C2 = capacitance of the second capacitor.

Given: C1 = 25 µF, C2 = 50 µF

Substitute into equation 1

Ct = (25×50)/(25+50)

Ct = 1250/75

Ct = 16.67 µF.

Using

Q = CV.................... Equation 2

Where Q = Charge, V = Voltage.

Given: V = 33 V, C = 16.67 µF = 16.67×10⁻⁶ F

Substitute into equation 2

Q = 33(16.67×10⁻⁶)

Q = 5.5×10⁻⁴ C.

Since both capacitors are connected in series, the same amount of charge flows through them.

Using,

E = 1/2Q²/C.................. Equation 3

Where E = Energy stored in the 25-µF capacitor

Given: Q =5.5×10⁻⁴ C, C = 25 µF = 25×10⁻⁶ F

Substitute into equation 3

E = 1/2(5.5×10⁻⁴)²/ 25×10⁻⁶

E = 6.05×10⁻³ J.

5 0
3 years ago
After driving a portion of the route, the taptap is fully loaded with a total of 26 people including the driver, with an average
Svet_ta [14]

Answer:

0.44807175m

Explanation:

k = Spring constant = 4\times 10^{4}\ N/m (Assumed, as it is not given)

g = Acceleration due to gravity = 9.81 m/s²

Total mass is

m=26\times 67+3\times 15+5\times 3+25\\\Rightarrow m=1827\ kg

The total weight will balance the spring force

mg=kx\\\Rightarrow x=\dfrac{mg}{k}\\\Rightarrow x=\dfrac{1827\times 9.81}{4\times 10^{4}}\\\Rightarrow x=0.44807175\ m

The springs are compressed by 0.44807175m

5 0
3 years ago
Easy one - giving brainly if correct.​
lana66690 [7]

Gas.

HOPE YOU GET 100!

4 0
2 years ago
A car engine changes chemical potential energy into the blank energy of the moving car​
kap26 [50]
<h3><u>Answer;</u></h3>

Kinetic energy

A car engine changes chemical potential energy into the <u>kinetic energy</u> of the moving car​.

<h3><u>Explanation;</u></h3>
  • A car engine converts potential chemical energy stored in gasoline into thermal energy and then into kinetic mechanical energy.
  • When gasoline undergoes combustion it reacts with oxygen to produce carbon dioxide and water vapor.Gasoline is a mixture of octane and similar hydrocarbons and contains potential chemical energy.
  • The hot exhaust gases from the combustion of gasoline that are produced within the cylinder expand and exert pressure, moving the piston in the cylinder outward then inward as the gas is exhausted. Kinetic mechanical energy of the moving pistons is transferred to the drive shaft and eventually to the wheels, giving the car kinetic mechanical energy.
7 0
3 years ago
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