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otez555 [7]
2 years ago
9

2). H2S and SO2 as follows,(8pt)

Chemistry
1 answer:
Naddik [55]2 years ago
5 0

Answer: 75.7 % yield

Explanation:

The balanced chemical equation is:

2H_2S+SO_2\rightarrow 3S+2H_2O  

According to stoichiometry :

68.2 g of H_2S will require = 64 g of SO_2

Thus 7.5 g of H_2S will require = \frac{64}{68.2}\times 7.5=7.0g of SO_2

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 68.2 g of give = 96 g of

Thus 7.5 g of H_2S give =\frac{96}{68.2}\times 7.5=10.5g  of S

% yield=\frac{\text{Actual yield}}{\text {Theoretical yield}}\times 100=\frac{7.95g}{10.5g}\times 100=75.7\%

Thus 75.7 % yield is there.

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