All categories

3 years ago

In which of the following instrument is the image that is formed erect

Physics

1 answer:

ipn [44]3 years ago

6 0

Answer:

C. microscope

Explanation:

A simple microscope is magnifying glass, an ordinary double convex lens having a short focal length that produces virtual and erect image.

You might be interested in

A student holding a 324Hz tuning fork approaches a wall at a speed of 6ms^(-1). The speed of sound in air is 336ms^(-1). What fr

Mashutka [201]

The frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

<h3>Frequency detected by the student</h3>

The observed frequency is determined by applying Doppler effect;

f' = f₀(v + v₀)/(v)

where;

f' is the observed frequency
v is speed of sound
v₀ is the source speed
f₀ is the original frequency

f' = 342(6 + 336)/(336)

f' = 348.1 Hz

Thus, the frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

Learn more about observed frequency here: brainly.com/question/10728818

#SPJ1

8 0

2 years ago

Identify whether each item is an example of science or technology.

Readme [11.4K]

Windmill- Science
Maglev Train- Technology

Hopefully these are right

7 0

3 years ago

State and prove bessel inequality

maria [59]

Statement :- We assume the orthagonal sequence ${{\{\phi\}}_{1}^{\infty}}$ in Hilbert space, now ${\forall \sf \:v\in \mathbb{V}}$ , the Fourier coefficients are given by:

${\quad \qquad \longrightarrow \sf a_{i}=(v,{\phi}_{i})}$

Then Bessel's inequality give us:

${\boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}$

Proof :- We assume the following equation is true

${\quad \qquad \longrightarrow \displaystyle \sf v_{n}=\sum_{i=1}^{n}a_{i}{\phi}_{i}}$

So that, ${\bf v_n}$ is projection of ${\bf v}$ onto the surface by the first ${\bf n}$ of the ${\bf \phi_{i}}$ . For any event, ${\sf (v-v_{n})\perp v_{n}}$

Now, by Pythagoras theorem:

${:\implies \quad \sf \Vert v\Vert^{2}=\Vert v-v_{n}\Vert^{2}+\Vert v_{n}\Vert^{2}}$

${:\implies \quad \displaystyle \sf ||v||^{2}=\Vert v-v_{n}\Vert^{2}+\sum_{i=1}^{n}\vert a_{i}\vert^{2}}$

Now, we can deduce that from the above equation that;

${:\implies \quad \displaystyle \sf \sum_{i=1}^{n}\vert a_{i} \vert^{2}\leqslant \Vert v\Vert^{2}}$

For ${\sf n\to \infty}$ , we have

${:\implies \quad \boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}$

Hence, Proved

5 0

2 years ago

Read 2 more answers

What is the number N0 of 99mTc atoms that must be present to have an activity of 15mCi?

svetoff [14.1K]

Base on my research, within 2 hours you have a number of atoms which remain.
N= N0*2^(-t/6.020 = N= N0*2^-0.33223= 07943 N0

So, the number of atoms that are being disintegrated is N0-N=N0*(1-0.79430)=0.2057 N0

It must be equal to 15 mCi = 15*3.7*10^7= 5.55*10^8 atoms

N0= 5.55*10*8/0.2057 = 2.698*10^9 atoms

Therefore, 2.698*10^9 atoms is the number of N0

4 0

3 years ago

Why should flexibility exercises be done in conjunction with strength-building exercises?

bixtya [17]

<span>Flexibility exercises should be done in conjunction with strength-building exercises because:

</span><span>They work together to maintain your overall level of fitness.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!

7 0

3 years ago

Read 2 more answers