2H2O=2H2+O2
37.4g H2O(1 mol/18.02)=2.07547 mol H2O
PV=nRT
(1.30)(V)=(2.07547)(.0821)(297)
Vwater=38.92898L
38.92898L (1 mol O2/2 mol H2O)=19.46449L O2 gas
Answer:
Amount of water in mL = 1.75⁹ × 10 ml (Approx)
Explanation:
Given:
Length of pool = 34 m
Width of pool = 31 m
Height of pool = 4.98 ft
Find:
Amount of water in mL
Computation:
1 ft = 0.3048 m
Height of pool = 4.98 (0.3048)
Height of pool = 1.5179 m
Volume of pool = (34)(31)(1.5179)
Volume of pool = 1,754.70 m³
1 m³ = 10⁶ ml
Amount of water in mL = 1,754.70 × 10⁶ ml
Amount of water in mL = 1.75⁹ × 10 ml (Approx)
Chemical is the chemical reactions mechanical is the physical reactions.
Answer:
The chemical formula is I2F9
Explanation:
Answer:
It is a molecular compound.
Explanation: