Answer:
I don't know but you got this!!
To solve this problem it is necessary to apply the concepts related to pressure as a unit that measures the force applied in a specific area as well as pressure as a measurement of the density of the liquid to which it is subjected, its depth and the respective gravity.
The two definitions of pressure can be enclosed under the following equations
Where
F= Force
A = Area
Where,
Density
g = Gravity
h = Height
Our values are given as,
If we make a comparison between the lid and the tube, the diameter of the tube becomes negligible.
Matching the two previous expressions we have to
Re-arrange to find h
Therefore the height of water in the tube is 7.9cm
Explanation:
(a) We know that the acceleration of the car is given by :
a = change in speed / time taken
If the speed of the car is constant in a straight line, the acceleration of the car is zero because there is no change in the speed of the car.
(b) For the driver steer a car traveling at constant speed so that the magnitude of the acceleration remains constant, the driver should drive the car in the circular path. This is because, in circular path the speed of an object remains the same while its velocity changes.
Answer:
5.71 N/m
Explanation:
From the question given above, the following data were obtained:
Extention (e) = 3.5 m
Force (F) = 20 N
Spring constant (K) =?
From Hooke's law,
F = Ke
Where :
F => is the force applied
e => is the extention caused by the force
K => is the spring constant
With the above formula, we can obtain the spring constant of the spring as follow:
Extention (e) = 3.5 m
Force (F) = 20 N
Spring constant (K) =?
F = Ke
20 = K × 3.5
Divide both side by 3.5
K = 20 / 3.5
K = 5.71 N/m
Thus, the spring constant of the spring is 5.71 N/m