1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
balu736 [363]
3 years ago
10

What is solvent!!?️​

Chemistry
2 answers:
Flura [38]3 years ago
3 0

Answer:

Solvent, substance, ordinarily a liquid, in which other materials dissolve to form a solution.

Mice21 [21]3 years ago
3 0

Answer :

A Substance that dissolves a solute, resulting in a solution.

If you don't know how to find it between the solvent and solute then the solvent is usually the one that is of more quantity.

You might be interested in
Balance : Fe2O3 + Zn = Fe+ZnO
zysi [14]

Answer:

Fe₂O₃ + 3Zn → 2Fe + 3ZnO

Explanation:

Step 1: RxN

Fe₂O₃ + Zn → Fe + ZnO

Step 2: Balance RxN

We need 2 Fe's on both sides.

We also need 3 O's on both sides.

  • If we multiply ZnO by 3, we will need 3 Zn's as well

Fe₂O₃ + 3Zn → 2Fe + 3ZnO

4 0
4 years ago
jeffrey is on his skateboard and starts skating down a ramp. ten seconds later he is traveling at 20.0m/s calculate the accelera
Grace [21]
Velocity/time= acceleration
7 0
3 years ago
Briefly explain formality in solution.
Zielflug [23.3K]

Answer:

Both molarity and formality express concentration as moles of solute per liter of solution. Formality is a substance's total concentration in solution without regard to its specific chemical form. ... The formality of a solution is defined as the number of formula mass of any solute dissolved in 1 litre of solution.

4 0
3 years ago
A gas has a temperature of 14 degrees C and volume of 4.5 liters. If the temperature is raised to 29 degrees C and the pressure
gladu [14]

Answer:

4.735

Explanation:

5 0
4 years ago
Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years
Sliva [168]

Answer : The time passed in years is 2.83\times 10^3\text{ years}

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = X g

a - x = amount left after decay process = 71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}

t=2831.00\text{ years}=2.83\times 10^3\text{ years}

Therefore, the time passed in years is 2.83\times 10^3\text{ years}

8 0
3 years ago
Other questions:
  • How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose
    12·1 answer
  • A measure of kinetic energy of particle motion within a substance is_____.
    6·2 answers
  • Suppose a carbon-14 nuclide decays into a nitrogen-14 nuclide by emitting an electron. complete the nuclear chemical equation be
    13·1 answer
  • A 0.1873 g sample of a pure, solid acid, H2X (a diprotic acid) was dissolved in water and titrated with 0.1052 M NaOH solution.
    9·1 answer
  • A student wants to classify some household chemicals by testing them using litmus paper. If she is going to classify these chemi
    5·1 answer
  • What's the control group and experiment group
    13·1 answer
  • Which one of the following is most likely to lose electrons when forming an ion?
    13·1 answer
  • Which substance is an ionic solid? A. LiCl B. HCl C. Ne D. Fe
    13·1 answer
  • Thermal energy always moves from a greater energy level to a lesser energy level
    10·1 answer
  • Write the value represented by 4.5x10-6 g
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!