Answer:
a)
b)
c)
Explanation:
From the question we are told that
Mass of soft rubber
Spring compression
Stiffness constant
Ball Distance
Frictional force
a)Generally the equation for motion of the second ball according to Newton's law is given by
b)Generally for speed to be at maximum spring force must equal frictional force
At distance
Therefore
Ball is at maximum speed at
c)Generally maximum velocity is represented mathematically as
<h2>Diagonal of circle </h2>
Explanation:
As the skateboarder wants to cross the play ground . The surface is rough .
As we know , the force of friction is non-conservative force . Thus work is required against this force .
We have formula:
work done = Force x distance (in one direction )
Te force applied cannot be changed , so he is to decrease the distance .
In case of circle , diameter is the minimum distance . Thus he is supposed to move along it .
Answer:
<u>The asteroid was not detected until it was extremely close to Earth. </u>
Explanation:
According to data from NASA, the Asteroid named 'Astriod 2019 OK', was detected when it was extremely close to earth with just about an estimated distance of 73,000 kilometers (45,000 miles) from the Earth.
Scientists were concerned at the proximity of this space object to the Earth before it was discovered, and it brought about a cause of concern that since it was not extremely large (estimated 57 to 130 meters wide) it creates a potential for other smaller asteroids to escape detection and struck the earth.
Answer:
vr = 5.39 m/s
Explanation:
vi = 16.9 m/s
∅ = 36.5º
d = 16.8 m
g = 9.81 m/s²
vr = ?
We have to get <em>Xmax = R</em> as follows
R = vi²*Sin (2∅) / g
⇒ R = (16.9 m/s)²*Sin (2*36.5º) / (9.81 m/s²)
⇒ R = 27.842 m
Now we can get t, using the formula:
R = vi*Cos ∅*t ⇒ t = R / (vi*Cos ∅)
⇒ t = (27.842 m) / (16.9 m/s*Cos 36.5º) = 2.049 s
We get x (the distance which the receiver must be run) as follows
x = R - d
⇒ x = 27.842 m - 16.8 m = 11.042 m
Finally we have
vr = x / t
⇒ vr = 11.042 m / 2.049 s = 5.39 m/s
Answer:
z = 0.8 (approx)
Explanation:
given,
Amplitude of 1 GHz incident wave in air = 20 V/m
Water has,
μr = 1
at 1 GHz, r = 80 and σ = 1 S/m.
depth of water when amplitude is down to 1 μV/m
Intrinsic impedance of air = 120 π Ω
Intrinsic impedance of water =
Using equation to solve the problem
E(z) is the amplitude under water at z depth
E_o is the amplitude of wave on the surface of water
z is the depth under water
now ,
taking ln both side
21.07 x z = 16.81
z = 0.797
z = 0.8 (approx)