Answer:
30.63 m
Explanation:
From the question given above, the following data were obtained:
Total time (T) spent by the ball in air = 5 s
Maximum height (h) =.?
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Total time (T) spent by the ball in air = 5 s
Time (t) taken to reach the maximum height =.?
T = 2t
5 = 2t
Divide both side by 2
t = 5/2
t = 2.5 s
Thus, the time (t) taken to reach the maximum height is 2.5 s
Finally, we shall determine the maximum height reached by the ball as follow:
Time (t) taken to reach the maximum height = 2.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
h = ½gt²
h = ½ × 9.8 × 2.5²
h = 4.9 × 6.25
h = 30.625 ≈ 30.63 m
Therefore, the maximum height reached by the cannon ball is 30.63 m
The correct answer would be the last option. The chemical reaction that would represent the combustion of methane would be CH4 + 2O2 = CO2 + 2H2O. Combustion reactions are reactions which involves a substance burning in oxygen. It always involve oxygen as a reactant. Usually, it is a reaction of a hydrocarbon and oxygen forming carbon dioxide and water. This type of reaction is a spontaneous reaction which means it happens readily. It does not any supply or input of energy for it to occur. The total kinetic energy of the reactants is equal or greater than the activation energy of the reaction.
Im pretty sure the answer is A.
Answer:
-4.1μC is the final charge on the third sphere
Explanation:
From the given data, q1 and q2 are brought into contact as they are both conductors, as such there will be evenly distribution of charges.
a) charge on each sphere(Q) = q1 + q2 / 2
= +3.8 μC + (- 2.6 μC) / 2 = 1.2μC/2 = 0.6μC
b) Now, one of those two spheres is brought into contact with the third sphere ; Q is brought into contact with q3 = Q + q3 / 2
= 0.6μC - 8.8 μC /2 = -8.2 μC/2
= -4.1μC is the final charge on the third sphere.
Answer:
1) 1.67eV
2) 505nm
Explanation:
The maximum kinetic energy of photoelectrons ,
KEmax=λhc−W=(0.3×10−6)(1.6×10−19)(6.62×10−34)(3×108)eV−2.46eV=1.67eV
If λ0 is the cut-off wavelength, W=λ0hc
or λ0=Whc=2.46×1.6×10−19(6.62×10−34)(3×108)=5.05×10−7m=505×10−9=505nm
<em>We know that the work function is the minimum photon energy for taking place of photoelectric effect. </em>