Give the positional isomers of 2 halopropane
(CH3)2CH
answer:
is in file download it
I'm not sure about part 1, you may need to google it, but part two is 11 protons, 11 electrons and 12 neutrons. You can find protons and electrons by just looking at the atomic number, and you can find neutrons by subtracting the atomic number from the atomic mass.
Answer:
Percent yield of SiC is 77.0%.
Explanation:
Balanced reaction: 
Molar mass of SiC = 40.11 g/mol
Molar mass of
= 60.08 g/mol
So, 100.0 kg of
=
moles of
= 1664 moles of 
According to balanced equation, 1 mol of
produces 1 mol of SiC
Therefore, 1664 moles of
produce 1664 moles of SiC
Mass of 1664 moles of SiC =
= 66743g = 66.74 kg (4 sig. fig.)
Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]
%
=
%
= 77.0%
Molality can be expressed by moles of solute over
kilograms of solvent. The question asks the molality of 0.25m NaCl. 0.25m NaCl
is equal to 0.25 moles of NaCl over 1 kg of water.