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3 years ago

What is one study trick you will use to remember the location and major features of the earth's core?

1 answer:

8 0

It is typically constructed and used by the geologists and seismologists. Thus, the global tectonic map is one of the important element that is to be remembered in order to remember the locations and the major features that are associated with the earth's crust

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Blake is setting up his tent at a renaissance fair. If the tent is 8 feet tall and the tether can be staked no more than 2 feet

Mariana [72]

The stake, height and tether length of the tent form a right angle triangle where the tether length is the hypotenuse.
Applying Pythagoras theorem:
length² = height² + (stake distance)²
length = √(8² + 2²)
length = 8.5 feet

3 0

3 years ago

Four copper wires of equal length are connected in series. Their cross-sectional areas are 1.6 cm2 , 1.2 cm2 , 4.4 cm2 , and 7 c

EleoNora [17]

Answer:

63.8 V

Explanation:

We are given that

$A_1=1.6 cm^2=1.6\times 10^{-4} m^2$

$1 cm^2=10^{-4} m^2$

$A_2=1.2 cm^2=1.2\times 10^{-4} m^2$

$A_3=4.4 cm^2=4.4\times 10^{-4} m^2$

$A_4=7 cm^2=7\times 10^{-4} m^2$

Potential difference,V=140 V

We know that

$R=\frac{\rho l}{A}$

According to question

$l_1=l_2=l_3=l_4=l$

In series

$R=R_1+R_2+R_3+R_4$

$R=\rho l(\frac{1}{A_1}+\frac{1}{A_2}+\frac{1}{A_3}+\frac{1}{A_4})$

$R=\rho l(\frac{1}{1.6\times 10^{-4}}+\frac{1}{1.2\times 10^{-4}}+\frac{1}{4.4\times 10^{-4}}+\frac{1}{7\times 10^{-4}})$

$R=\rho l(18284.6)$

$I=\frac{V}{R}=\frac{140}{\rho l\times 18284.6}$

Potential across 1.2 square cm= $V_1=IR_1=\frac{140}{\rho l\times 18284.6}\times \rho l(\frac{1}{1.2\times 10^{-4}}=63.8 V$

Hence, the voltage across the 1.2 square cm wire=63.8 V

3 0

3 years ago

Define sporulation and fragmentation

Andrei [34K]

Answer:

Sporulation

the formations of spores from vegetative cells during unfavorable environmental conditions

Fragmentation

The asexual reproduction, where the body of the organism breaks into smaller pieces

5 0

3 years ago

Read 2 more answers

A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s^2, find the force

Harman [31]

We know that m = 5 kg
a = 3.0 m/s^2
g = 9.8 (since not written, lets assume it's an international standard)

T - mg = ma

T = mg + ma

T = (5 . 9.8) + (5 . 3 )

T = 49 + 15

T = 64 N

Hope this helps

3 0

3 years ago

Read 2 more answers

if a freely falling object were somehow equipped with a speedometer on a planet where the acceleration due to gravity is 20 m/s/

Pie

Answer: The speed reading would increase each second by 20m/s

Explanation:

Acceleration is the change in velocity per unit change in time.

Acceleration = velocity/time

∆v = a∆t

Given a = g = 20m/s/s (acceleration due to gravity)

∆t = 1 sec

∆v = 20m/s/s × 1s

∆v = 20m/s

Therefore, the speed reading would increase each second by 20m/s

3 0

4 years ago