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natta225 [31]
3 years ago
7

Select the correct characteristics describing normal-phase and reversed-phase chromatography. Normal-phase chromatography Revers

ed-phase chromatography (a) Polarity of phases: 1. Stationary phase is polar 2. Stationary phase is non polar b) Eluent strength of solvent. 1. Increases as solvent becomes more polar. 2. Increases as solvent becomes less polar c) Nature of solutes. 1. Polar 2. Non-polar d) Nature of solute interaction. 1. More soluble in mobile phase as the polarity of the mobile phase increases. 2. More soluble in mobile phase as the polarity of the mobile phase decreases. e) Polarity of phases: 1. Stationary phase is polar 2. Stationary phase is non-polar f) Eluent strength of solvent: 1. Increases as solvent becomes more polar. 2. Increases as solvent becomes less polar. g) Nature of solutes: 1. Polar 2. Non-Polar h) Nature of solute interaction: 1. More soluble in mobile phase as the polarity of the mobile phase increases. 2. More soluble in mobile phase as the polarity of the mobile
Chemistry
1 answer:
qwelly [4]3 years ago
3 0

Answer:

(a) Polarity of phase: 1. Stationary phase is polar

b) Eluent strength of solvent:  1. Increases as solvent becomes more polar

c) Nature of solutes.1. Polar

d) Nature of solute interaction:2. More soluble in mobile phase as the polarity of the mobile phase decreases

e) Polarity of phases: 1. Stationary phase is polar

f) Eluent strength of solvent: 1. Increases as solvent becomes more polar.

g) Nature of solutes: 1. Polar

h) Nature of solute interaction: 2. More soluble in mobile phase as the polarity of the mobile

Explanation:

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A 10 gram sample of water is heated to 105 ℃ and is mixed with a 25 gram sample of water cooled to 25℃ . What is the final tempe
lesya692 [45]

Answer:

The final temperature of the water mixture is 47.85°C

Explanation :

Given,

For Warm Water

mass = 10grams

Temperature = 105°C

For Cold Water

mass = 25grams

Temperature = 25°C

When a sample of warm water is mixed with a sample of cool water,

The energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:

<h3>Qlost = Qgain</h3>

However,

Q = (mass) (ΔT) (Cp)

Cp = Specific heat of water = 4.184 J/Kg°C

So,

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using is FINAL temperature. This is what we are solving for.  

The warmer water goes down from to 105°C to x, so this means its Δt equals 105°C − x. The colder water goes up in temperature, so its Δt equals x − 25℃

Substituting the values,

(10)( 105°C − x)(4.184) = (25)(x − 25℃)(4.184)

Solving for x, we get

x = 47.85°C

Therefore, The final temperature of the water mixture is 47.85°C.

8 0
3 years ago
You are to give ampicillin, with a recommended dose of 25 mg/kgmg/kg , to a child with a mass of 24 kgkg . If stock on hand is 2
Anastasy [175]

Answer:

2.4 capsules

Explanation:

You are to give ampicillin, with a recommended dose of 25 mg/kg (25 mg of ampicillin per kg of body weight), to a child with a mass of 24 kg. The mass of ampicillin to be given is:

24 kg body mass × (25 mg ampicillin/ 1 kg body mass) = 600 mg ampicillin

The stock on hand is 250 mg/capsule (250 mg ampicillin per capsule). The number of capsules required to supply 600 mg of ampicillin is:

600 mg ampicillin × (1 capsule/250 mg) = 2.4 capsule

4 0
3 years ago
A sample of 1L of gas in a container at-73C has a pressure of 32.2inHg. To
Goryan [66]

Answer:

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Explanation:

8 0
3 years ago
English
alisha [4.7K]
The answer is 250 cm^3.
5 cm x 5 cm x 10 cm = 250 cm^3
5 0
4 years ago
What is the balanced equation for KOH+CO2—&gt;K2CO3+H2O
insens350 [35]

The balanced equation :

2KOH+CO₂⇒K₂CO₃+H₂O

<h3>Further explanation</h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

KOH+CO₂⇒K₂CO₃+H₂O

  • give coeffiecient

aKOH+bCO₂⇒K₂CO₃+cH₂O

  • make equation

K, left=a, right=2⇒a=2

H, left=a, right=2c⇒a=2c⇒2=2c⇒c=1

O, left=a+2b, right=3+c⇒a+2b=3+c⇒2+2b=3+1⇒2b=2⇒b=1

the equation becomes :

2KOH+CO₂⇒K₂CO₃+H₂O

3 0
3 years ago
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