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mezya [45]
3 years ago
12

Which quantity can be calculated using the equation E=MC^2

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

The energy needed to split an atom into separate protons, neutrons, and electrons

Explanation:

The equation E = MC^2 is developed by Einstein’s Special Relativity Theory

where,

E = Energy

M = mass

C = speed of the light

The energy should be measured in Joules i.e J

The mass should be measured in Kilogram i.e Kg

And, the speed of the light should be measured in meters per second i.e ms-1

The C should be squared

Now the energy is required to divided into three particles i.e protons, electrons and neutrons

It also needs to allocate the nucleus into distinct protons and neutrons that we called binding energy of nuclear

And if the energy is required to take off an electron from an atom we called the energy of ionization

And if the energy is required to add an electron to an atom so we called it affinity of electron

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3.95 g of sugar (C6H12O6) is dissolved in water to make 158 mL of solution. Find the molarity.
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Answer:

[C₆H₁₂O₆] = 0.139 M

Explanation:

Molarity si defined as a sort of concentration. It indicates the moles of solute that are contained in 1 L of solution.

We can also say, that molarity are the mmoles of solute contained in 1 mL of solution.

For this case, the solute is sugar (glucose). Let's determine M (mmol/mL)

(3.95 g . 1mol / 180g) . (1000 mmol / 1mol) / 158 mL

We determine moles, we convert them to mmoles, we divide by mL

M = 0.139 M

Moles = 3.95 g . 1mol / 180g → 0.0219 mol

We convert mL to L → 158 mL . 1L/1000mL = 0.158L

M = 0.0219 mol / 0.158L = 0.139 M

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250 mL of a solution of calcium oxalate is the evaporated until only a residue of solid calcium
Lana71 [14]

Answer:

2.3 * 10^-5

Explanation:

Recall that the solubility of a solute is the amount of solute that dissolves in 1 dm^3 or 1000cm^3 of solution.

Hence;

Amount of calcium oxalate = 154 * 10^-3/128.097 g/mol = 1.2 * 10^-3 mols

From the question;

1.2 * 10^-3 mols dissolves in 250 mL

x moles dissolves in 1000mL

x = 1.2 * 10^-3 mols * 1000/250

x= 4.8 * 10^-3 moldm^-3

CaC2O4(s) ------->Ca^2+(aq) + C2O4^2-(aq)

Hence Ksp = [Ca^2+] [C2O4^2-]

Where;

[Ca^2+] = [C2O4^2-] = 4.8 * 10^-3 moldm^-3

Ksp = (4.8 * 10^-3)^2

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