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2 years ago

13

Which part of a machine control unit interacts with the machine tools through electric signals?=]

1 answer:

FrozenT [24]2 years ago

4 0

Answer:

control loop unit

Explanation:

Edmentum/Plato

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Dmitriy789 [7]

Answer:

4. A series of steps engineers use to solve problems.

Explanation:

The process of engineering design is a sequence of procedures that engineers pursue to arrive at a solution to a specific problem. Most times the solution includes creating a product such as a computer code, which fulfills certain conditions or performs a function. If the project in-hand includes designing, constructing, and testing it, then engineers probably adopt the design process. Steps of the process include defining the problem, doing background research, specifying requirements, brainstorming solutions, etc.

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3 years ago

A three-point bending test is performed on a glass specimen having a rectangular cross section of height d = 5.4 mm (0.21 in.) a

Fudgin [204]

Answer:

5.21e-2mm

Explanation:

Please see attachment

8 0

3 years ago

Starting with the column in Problem 1, perform enough additional calculations to determine the effects of increasing fc from 500

Hoochie [10]

Answer:

Explanation:

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5 0

3 years ago

Find the toughness (or energy to cause fracture) for a metal that experiences both elastic and plastic deformation. Assume Equat

PtichkaEL [24]

Answer:

Detailed solution is attached below in three simple steps the problem is solved.

7 0

3 years ago

The pilot of an airplane reads the altitude 6400 m and the absolute pressure 45 kPa when flying over the city. Calculate the loc

garri49 [273]

Answer:

1) The absolute pressure equals = 96.98 kPa

2) Absolute pressure in terms of column of mercury equals 727 mmHg.

Explanation:

using the equation of pressure statics we have

$P(h)=P_{surface}-\rho gh...............(i)$

Now since it is given that at 6400 meters pressure equals 45 kPa absolute hence from equation 'i' we obtain

$P_{surface}=P(h)+\rho gh$

Applying values we get

$P_{surface}=45\times 10^{3}+0.828\times 9.81\times 6400$

$P_{surface}=96.98\times 10^{3}Pa=96.98kPa$

Now the pressure in terms of head of mercury is given by

$h_{Hg}=\frac{P}{\rho _{Hg}\times g}$

Applying values we get

$h=\frac{96.98\times 10^{3}}{13600\times 9.81}=0.727m=727mmHg$

7 0

3 years ago