When comparing plant and animal cells which statement is least accurate?

Chemistry

2 answers:

IrinaK [193]3 years ago

8 0

Here is a diagram comparing both plant and animal cells.
Hope it helps:)

Yanka [14]3 years ago

5 0

Answer:

Explanation:

I answered late sorry

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Magnesium is a group 2 metal which exists as a number of isotopes and forms many compounds.

HACTEHA [7]

Answer:

Traces of sodium impurity

Explanation:

Metal ions are identified by a characteristic colour imparted to flame by the metal ion solution. Various metals have various colours which they impart to a flame.

The energy of a flame is not sufficient for the excitation of electrons of Mg to a higher energy level. As a result of this, Mg do not give any color in Bunsen flame.

However, a few tinges of yellow-orange colour which is characteristic of sodium metal do appear when magnesium ions are exposed to a flame as a consequence of traces of sodium impurity in the magnesium ion solution.

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4 years ago

A gas has a density of 3.21 g/L at stp what is the gas

Flauer [41]

The gas is bromine. (This is a fact)

4 0

2 years ago

Boron trifluoride gas is collected at in an evacuated flask with a measured volume of . When all the gas has been collected, the

Vaselesa [24]

Answer:

0.683 mol

46.3 g

Explanation:

There is some info missing. I think this is the original question.

Boron trifluoride gas is collected at 21.0 °C in an evacuated flask with a measured volume of 50.0 L. When all the gas has been collected, the pressure in the flask is measured to be 0.330 atm. Calculate the mass and number of moles of boron trifluoride gas that were collected. Round your answer to 3 significant digits.

Step 1: Convert the temperature to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 21.0°C + 273.15

K = 294.2 K

Step 2: Calculate the moles of boron trifluoride gas

We will use the ideal gas equation.

$P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{0.330atm \times 50.0L}{\frac{0.0821atm.L}{mol.K} \times 294.2K} = 0.683 mol$